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Why isn't string splitting after last open parenthesis?


Why isn't string splitting after last open parenthesis?

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Why isn't string splitting after last open parenthesis?
Tag : r , By : Aki Björklund
Date : November 26 2020, 04:01 AM

I hope this helps . I'm trying to split the string by the last occurrence of the left ("(") parenthesis, but for some reason, R and stringr::str_split isn't recognizing this. , You may use
"\\((?=[^(]*$)"
> library(stringr)
> str_split("Ben Meyers (1), Hank Crone (1) (PP)", "\\((?=[^(]*$)", simplify = TRUE)
     [,1]                              [,2] 
[1,] "Ben Meyers (1), Hank Crone (1) " "PP)"
"\\s*\\((?=[^(]*$)"
 ^^^^

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Splitting string by a colon that is NOT contained within parenthesis ()


Tag : javascript , By : Vlad Sirenko
Date : March 29 2020, 07:55 AM
I wish this helpful for you There is a good reason why you were unable to find a regular expression for your problem:
The language you describe is not regular, i.e. it cannot be parsed with a regular expression.
// Pseudo code
int depth = 0;
List<int> breakIndices;
for int index = 0 .. input.length-1:
  switch(input[index])
    ':': if (depth==0) breakIndices.add(index); break;
    '(': depth++; break;
    ')': depth--; break;
    default: break;
// Now, all indices of the colons you need are in the breakIndices list.

splitting the string and choosing the middle part containing two set of parenthesis


Tag : chash , By : Tony Z
Date : March 29 2020, 07:55 AM
wish helps you As I know for selecting a part of a string we use split. For example, if node1.Text is test (delete) if we choose delete , You can also use regex, and then just remove the parentheses:
resultString = Regex.Match(yourString, @"\((.*?)\)").Value.
               Replace("(", "").Replace(")", "");
Regex.Match(yourString, @"\((.*?)\)").Groups[1].Value;
List<string> matches = new List<string>();
var result = Regex.Matches(yourString, @"\((.*?)\)");
foreach(Match x in result)
      matches.Add(x.Groups[1].Value.ToString());

splitting parameters in a string with parenthesis


Tag : cpp , By : user150694
Date : March 29 2020, 07:55 AM
wish of those help Since you can't use C++11, then some basic string spliting with std::stringstream might do the job. I'm not sure whenever is part of C++11, but you can easily replace them with another maximum value.
#include <iostream>
#include <string>
#include <vector>
#include <sstream>
#include <limits>

int main()
{
    double beginOfLine = 0.0, endOfLine = 0.0;
    std::vector<int> vec1;
    std::vector<int> vec2;

    std::stringstream ss("1.  (10 10) (10 15) (2 11) 2.");

    ss >> beginOfLine;

    while (true) {
        int first, second;
        ss.ignore(std::numeric_limits<std::streamsize>::max(), '(');
        ss >> first >> second;
        vec1.push_back(first);
        vec2.push_back(second);
        ss.ignore(std::numeric_limits<std::streamsize>::max(), ')');
        ss.ignore(std::numeric_limits<std::streamsize>::max(), ' ');

        if (ss.peek() != '(') {
            ss >> endOfLine;
            break;
        }
    }

    std::cout << beginOfLine << '\n';
    for (std::vector<int>::iterator it = vec1.begin(); it != vec1.end(); ++it)
        std::cout << *it << ' ';
    std::cout << '\n';
    for (std::vector<int>::iterator it = vec2.begin(); it != vec2.end(); ++it)
        std::cout << *it << ' ';
    std::cout << '\n' << endOfLine;
    return 0;
}

Splitting string by parenthesis


Tag : chash , By : fstender
Date : March 29 2020, 07:55 AM

java Regular expression while splitting a string over parenthesis


Tag : java , By : Per
Date : March 29 2020, 07:55 AM
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