write a c function that generates one random number, or a pair of random numbers, or a triplet of random numbers given t
Tag : c , By : Tamizhvendan
Date : March 29 2020, 07:55 AM
With these it helps If the range is small enough, you shouldn't have problems in using the usual modulo method int GetRandomInt(int Min, int Max)
{
return (rand()%(Max-Min+1))+Min;
}
int GetRandomInt(int Min, int Max)
{
return (int)(((double)rand())/MAX_RAND*(Max-Min))+Min;
}
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Very non-random factor of Math.random when filling an array with random numbers
Tag : java , By : KaoFloppy
Date : March 29 2020, 07:55 AM
will be helpful for those in need It doesn't matter what numbers your random number generator comes up with. So long as your array has an even length, the sum that you calculate using that function will always be zero.
Let's prove this mathematically. Let's say we have an array of four elements: [A, B, C, D]. (The values don't matter, and I'll prove it.)
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Creating an object of Random class or using Math.random() in order to generate random numbers
Date : March 29 2020, 07:55 AM
I wish this help you Math.random() uses the Random class. And it's basically calling nextDouble() on the Random object of the Math class.
However the first method is definitely easier to understand and use. And has more options then the Math class has. So I'd go with the Random class if you need a lot of Random numbers or if you need types other then double. And I'd use Math.random() when you only need a double between 0 and 1.
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Use Random.random [30,35] to print random numbers between 30,35. Seed(70)
Tag : python , By : Carlos Galdino
Date : March 29 2020, 07:55 AM
wish of those help The output [blah, blah, blah] indicates that it is a list of numbers rather than a series of numbers printed one-by-one. In addition, if you want random floating point values, you'll need to transform the numbers from random.random (which are zero to one) into that range. import random # Need this module.
def problem2_4():
random.seed(70) # Set initial seed.
nums = [] # Start with empty list.
for _ in range(10): # Will add ten values.
nums += [random.random() * 5 + 30] # Add one value in desired range.
print(nums) # Print resultant list.
import random
random.seed(70)
print([random.random() * 5 + 30 for _ in range(10)])
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How to generate uniform random numbers using random.random()
Date : March 29 2020, 07:55 AM
Hope that helps I want to generate uniform random number in a range 'n' by using random.random() in python. , For Integers:
int(random.uniform(0, 1) * n) will be 0 to n - 1
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