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Function to find varying strings


Function to find varying strings

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Function to find varying strings
Tag : r , By : k19k
Date : November 25 2020, 04:01 AM

it should still fix some issue I need to do the following as a homework assignment and I am struggling to find the right answer: , We can make use of ignore.case = TRUE in grep
find.names = function(df, str){
     df$name[grep(str, df$text, ignore.case = TRUE)]

   }

find.names(wiki, "Carnegie Mellon")

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Why does my function only return 0 when searching through strings to find certain sub strings?


Tag : java , By : Mariamario
Date : March 29 2020, 07:55 AM
like below fixes the issue The point of this function is to search through the string to find substrings such that it starts with "foo" and ends in "bar". , Because this:
s.substring(startCharacter, startCharacter + 2)
if (s.substring(startCharacter, startCharacter + 3).equals("bar"))

Powershell find common strings varying number of arrays


Tag : arrays , By : afarouk
Date : March 29 2020, 07:55 AM
help you fix your problem This is easy. You say you have two-dimensional array $j and want to find all strings that exist in all elements of $j. You create a temporary "total intersection" array out of $j[0] then run foreach on $j and create an intersection into that temporary. At the end it'll only contain those elements that all of the columns contain.
# $j is two-dimensional, and has unique elements
$t=$j[0]
$j | % {
    $i=$_ #rename to avoid confusion
    if ($i -ne $j[0]) { $t = $t|where {$i -contains $_}}
}
# $t now has your intersection

A PL/pgSQL function with varying return type (and varying inner query)


Tag : sql , By : kennystone
Date : March 29 2020, 07:55 AM
I hope this helps you . I have two comments to the first solution.
First, use or %I or quote_ident() in format() function, not both. Compare:
with q(s) as (
    values ('abba'), ('ABBA')
    )
select 
    quote_ident(s) ok1, 
    format('%I', s) ok2, 
    format('%I', quote_ident(s)) bad_idea
from q;

  ok1   |  ok2   |  bad_idea  
--------+--------+------------
 abba   | abba   | abba
 "ABBA" | "ABBA" | """ABBA"""
(2 rows)    
create or replace function my_select(into_table text, tbl text, order_by text default null)
returns void as $function$
declare
    q text;
begin
    q := 'select * from ' || quote_ident(tbl);
    if order_by is not null then
        q := q || ' order by ' || order_by;
    end if;
    execute format($$
        create temp table %I
        on commit drop
        as %s
    $$, into_table, q);
end
$function$ language plpgsql;

begin;
select my_select('my_tmp', 'my_data1', 'id');
select * from my_tmp;
commit;

BEGIN
 my_select 
-----------

(1 row)

 id | val 
----+-----
  1 | a
  2 | c
  3 | d
  4 | b
(4 rows)

COMMIT

Python3: Is there a way to split a list of strings into separate lists, considering that the strings are of varying leng


Tag : python , By : Giles
Date : March 29 2020, 07:55 AM
Hope this helps For example: , Check this
>>> list_string = ["This is a string that I want."
, "this is also a string that I want!"
, "and this"
, "and also this one!!"]
>>> [[i] for i in list_string]
[['This is a string that I want.'], ['this is also a string that I want!'], ['and this'], ['and also this one!!']]
>>> 

How to disambiguate repeated strings by appending varying length strings?


Tag : r , By : fstender
Date : March 29 2020, 07:55 AM
hop of those help? We can take advantage of make.unique by striping the numbers that make the characters unique, and using them (... + 1) as reference as to how many characters to append, i.e.
i1 <- as.numeric(gsub('\\D+', '', make.unique(x)))
i1[is.na(i1)] <- 0 #because where there is no number it returns NA
paste0(x, sapply(i1 + 1, function(i) paste(rep(' ', each = i), collapse = '')))
#[1] "a "   "b "   "c "   "a  "  "b  "  "a   " "c  "  "d "   "e "
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