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Firebase Swift querying for symbols


Firebase Swift querying for symbols

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Firebase Swift querying for symbols
Tag : swift , By : Brianna
Date : January 12 2021, 08:33 AM

help you fix your problem What you think is happening isn't. Let me explain and provide an example:
It appears your are trying to perform a string search. Perhaps even a substring search.
queryStarting(atValue: "[a-zA-Z0-9]*")
posts
  post_x
    description: "[a-zA-Z0-9]* This node would be returned"
.startWith: a query that starts with the given string
.endWith: a query ending with a string that starts with the given string
        (not the ending part of a string or a substring)
posts
  post_1
    description: "This is a post! #thisdoesntwork"
  post_2
    description: "Heres another post! #neitherdoesthis"
  post_3
    description: "a"
  post_4
    description: "n"
    let postsRef = ref.child("posts")
    let queryRef = postsRef.queryOrdered(byChild: "description")
                           .queryStarting(atValue: "This")
                           .queryEnding(atValue: "z")
    queryRef.observeSingleEvent(of: .value) { snapshot in
        print(snapshot)
    }
items
  item_0
   description: fruit_apple
  item_1
   description: fruit_banana
  item_2
   description: nut_peanut
  item_3
   description: nut_walnut
    let queryRef = postsRef.queryOrdered(byChild: "description")
                           .queryStarting(atValue: "fruit_")
                           .queryEnding(atValue: "fruit_")
33  !
34  \"
35  #
36  $
37  %
38  &
39  '
40  (
41  )
42  *
43  +
44  ,
45  -
46  .
47  /

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What is the exact way of Firebase (3.2.0) Querying with Swift (2.0)?


Tag : swift , By : 小和尚
Date : March 29 2020, 07:55 AM
Hope this helps I have been trying to query through my firebase database by using their guides but I'm unable to return results appropriately. If someone can point out what I'm doing wrong or correct me, it will be very helpful. , I continued testing and changed the way i would get my result by
 MyQuery1.observeSingleEventOfType(.Value, withBlock: {
            snapshot in
            print("************")
            print("Ordered by Value")
            for snap in snapshot.children {
                print(snap);
            }
        })
Ordered by Value
Snap (Okay) 1
Snap (Lets) 3
Snap (beep) 4
Snap (boop) 11
Snap (Alright) 24
Snap (Gamma) Alphaa
Snap (Beta) Betaa
Snap (Delta) Deltaa
Snap (Epsilon) Epsilonn
Snap (Eta) Etaa
Snap (Alpha) Gammaa
Snap (Iota) Iotaa
Snap (Theta) Thetaa
Snap (Zeta) Zetaa

Swift and Firebase querying the database


Tag : swift , By : Comfly
Date : March 29 2020, 07:55 AM
Hope that helps I am trying to create a tableView of chats the user is a part of. I was following the firebase tutorials on their site and they said to easily get a list of chat rooms the user is a part of to create a child and add the names of the rooms to that child. , The code you are using is the challenge. Here's a simplified version:
let usersRef = firebase.child("users")
let thisUser = usersRef.childByAppendingPath(fUID)
let thisUsersRooms = thisUser.childByAppendingPath("rooms")

thisUsersRooms.observeSingleEventOfType(.Value, withBlock: { snapshot in

     if ( snapshot.value is NSNull ) {
          print("not found")
     } else {
          for child in snapshot.children {
               let roomName = child.key as String
               print(roomName) //prints each room name
               self.roomsArray.append(roomName)
          }

          self.myRoomsTableView.reloadData()
     }
})

Querying Firebase with Swift 3.0


Tag : ios , By : Ashley
Date : March 29 2020, 07:55 AM
help you fix your problem You need to use queryOrderedByChild to createdAt and than use equalTo Today
let ref = FIRDatabase.database().reference().child("thoughts").queryOrdered(byChild: "createdAt").queryEqual(toValue : "Today")

ref.observe(.value, with:{ (snapshot: FIRDataSnapshot) in
    for snap in snapshot.children {
        print((snap as! FIRDataSnapshot).key)
    }
})

Firebase and querying for a term in Swift


Tag : swift , By : Tim Benninghoff
Date : March 29 2020, 07:55 AM
To fix the issue you can do Since you're using queryEqualToValue, you will only get results where the userComment matches exactly with the value you specified.
If you want results where userComments starts with the value, you should use a combination of queryStartingAtValue and queryEndingAtValue:
DataService.dataService.BASE_REF.child("Posts").
    child(selectedComment.commentKey).child("comments").
    queryOrderedByChild("userComment")
    .queryStartingAtValue(comment). queryEndingAtValue(comment+"\uF8FF")
    observeSingleEventOfType(.Value, withBlock: { (snapshot) in

Swift Firebase querying


Tag : swift , By : Chris Tattum
Date : March 29 2020, 07:55 AM
To fix this issue You have to define Firebase Database indexes in the location where you execute the query. So that is one level higher than where you currently have it:
{
  "rules": {
    "users": {
      ".indexOn": ["email"],
      ".read": "auth != null",
      "$uid": {
        ".write": "$uid === auth.uid",
      }
    }
  }
}
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