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class hierarchy in TypeScript


class hierarchy in TypeScript

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class hierarchy in TypeScript
Tag : angular , By : rhinojosa
Date : January 12 2021, 08:33 AM

seems to work fine You should check Mixins in TypeScript
class EditableSortableList implements SortableList, EditableList {
    //Properties and empty methods of both SortableList and EditableList only to satisfy the interfaces. They will be overridden in the next line.
}

applyMixins(EditableSortableList, [SortableList, EditableList]);
function applyMixins(derivedCtor: any, baseCtors: any[]) {
    baseCtors.forEach(baseCtor => {
        Object.getOwnPropertyNames(baseCtor.prototype).forEach(name => {
            derivedCtor.prototype[name] = baseCtor.prototype[name];
        });
    });
}

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How to manage a multiple-level class hierarchy in nhibernate with table per class hierarchy strategy?


Tag : chash , By : ianium
Date : March 29 2020, 07:55 AM
Hope this helps I'm not that familiar with c# and NHibernate but are you sure Activity should be set as abstract="true" in the mapping? It looks like the Activity class isn't abstract.
Shouldn't Running and Talking reside inside of Activity else the StartTime won't be saved. Right?
<subclass name="Activity"
...
  <subclass name="Running"
  ...
  </subclass>
  <subclass name="Talking"
  ...
  </subclass>
...
</subclass>
...
WHERE foo IN (null)
<property name="show_sql">true</property>
<property name="hibernate.format_sql">true</property>
<property name="hibernate.use_sql_comments">true</property>

creating static-like class or module hierarchy in TypeScript?


Tag : typescript , By : moss
Date : March 29 2020, 07:55 AM
this will help I am trying to create a "global" configuration structure for our website's javascript. What I want to be able to do is something like that: , You could just use modules:
module company.config {
    export var serviceUrl = 'http://...';
    export var serviceKey = '1234567890';
}
module company {
    export class config {
        static serviceUrl = 'http://...';
        static serviceKey = '1234567890';
    }
}

PHP: Lower hierarchy class access public function from upper hierarchy class


Tag : php , By : damomurf
Date : March 29 2020, 07:55 AM
will be helpful for those in need To access Upper::foo() from Lower::bar() you have to pass the $this variable as argument:
In class Lower:
public function bar (Upper $upper) {
    $upper->foo();
}
$this->lower->bar($this);
Upper::foo(); // calls static method foo of class Upper

TypeScript class in traditional folder hierarchy


Tag : java , By : Praetoriansentry
Date : March 29 2020, 07:55 AM
hope this fix your issue Organizing your typescript classes into 1-class per file and an organized folder hierarchy is perfectly acceptable and even encouraged in typescript.
If using typescript 2.0 or above your paths do not need to be relative. You can use the baseUrl: property to specify where non-relative (i.e. no . or ..) paths are rooted. For example of you had:
tsconfig.json 
src/
   foo/
       foo.ts
   bar/
       bar.ts
src/
    com/
        ancient/
            my-type.ts
export class MyType{
     constructor(){
        console.log('Hello World');
     }
}
import {MyType} from 'com/ancient/my-type'

typescript class and namescript hierarchy when do importing


Tag : angular , By : jaredsmiller
Date : March 29 2020, 07:55 AM
should help you out Class export will be overridden by a namespace if a namespace is non-empty:
export class Foo { }

export namespace Foo {
    let bar;
}
var Foo = /** @class */ (function () {
    function Foo() {
    }
    return Foo;
}());
exports.Foo = Foo;
(function (Foo) {
    var bar;
})(Foo = exports.Foo || (exports.Foo = {}));
exports.Foo = Foo;
export class Foo { }

export namespace Foo {
    // let bar;
}
var Foo = /** @class */ (function () {
    function Foo() {
    }
    return Foo;
}());
exports.Foo = Foo;
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