A different statement for each for-loop iteration
Tag : matlab , By : Jason Jennings
Date : March 29 2020, 07:55 AM
seems to work fine In a 1xn array, n alphabets will be stored. That is why you see first three letters getting printed (i=1:3). Assuming all the statements do not have the same length, you could save A,B,C in a cell array. Then access it as usual. v={A;B;C};
for i = 1:size(v,1) %always try to use size(v,1) instead of hard-coding.
fprintf('%s',v{i,1})
end
v=[A;B;C];
for i = 1:size(v,1) %always try to use size(v,1) instead of hard-coding.
fprintf('%s',v(i,:))
end
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Statement-terminator (;) operator after iteration statement: Ends the iteration statement itself, or an invisible empty
Date : November 06 2020, 03:01 PM
will be helpful for those in need From a grammar standpoint, it terminates the statement. That's a pretty odd way to think about it though. while loops must have a body, so if you just write while(true)
while (true) i++;
while (true) ;
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it statement inside loop iteration for each expect statement, mocha
Date : March 29 2020, 07:55 AM
it fixes the issue I have this array of objects. , You might want to use forEach instead of map. const expect = require('chai').expect;
describe('links', function() {
let links = [
{
url: 'some url 1',
status: 200
},
{
url: 'some url 2',
status: 200
}
]
links.forEach(function(property) {
it('link array to contain url string', function() {
expect(property).to.have.property('url').to.be.a('string');
});
it('link array to contain status number', function() {
expect(property).to.have.property('status').to.be.a('number');
});
});
});
> mocha
links
√ link array to contain url string
√ link array to contain status number
√ link array to contain url string
√ link array to contain status number
4 passing (14ms)
before(function() {
it('will NOT work here', function() { });
});
it('will work here', function() {
it('will NOT work here', function() { });
});
describe('links', function() {
let links = [];
before(function() {
links = [
{
url: 'some url 1',
status: 200
},
{
url: 'some url 2',
status: 200
}
];
});
// This won't work...
links.forEach(function(property) {
// .. since links is still an empty array when this runs
it('should...', function() { /* ... */ });
});
});
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Using for loop iteration with If statement
Tag : python , By : Praetoriansentry
Date : March 29 2020, 07:55 AM
wish helps you It is printed multiple times, because there are multiple times where the current value does not match. A simple way to fix this is to use a flag, like so: value_found = False
for x in range(len(regs)):
rex = regs[x]
if re.match(rex,hostname):
print (dev[x],'Regex matched')
value_found = True
break
if not value_found:
print('wrong_format')
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For loop statement not reading if statement to continue to next iteration
Date : March 29 2020, 07:55 AM
seems to work fine You seem to be comparing the value incorrectly. You are trying to compare a string "5" to an integer 5. if item.data["position"] == '5':
print(1 == "1")
print(1 == 1)
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