Text message not being sent to a list of numbers but is sent when just one number is specified

Text message not being sent to a list of numbers but is sent when just one number is specified

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Text message not being sent to a list of numbers but is sent when just one number is specified
Tag : java , By : user185939
Date : November 28 2020, 03:01 PM

should help you out Since the sendTextMessage() method only can take one number at a time, you need to execute this method for each number in the list.
That being said you should 'loop' through that List. Like this:
for (String number : numbers) {
    smsManager.sendTextMessage(numbers, null, message, null, null);

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why this error? The system cannot find message text for message number 0x2331 in the message file for Application

Tag : perl , By : KT.
Date : March 29 2020, 07:55 AM
This might help you Ref: http://www.febooti.com/products/automation-workshop/online-help/events/run-dos-cmd-command/exit-codes/
0x2331 means Program is not recognized as an internal or external command, operable program or batch file.
system("cmd /k ren ref.txt ref1.txt");
system("ren ref.txt ref1.txt");

I have a column of text and text-formatted-numbers. If number;convert. If text;return text

Tag : excel , By : mediafarm
Date : March 29 2020, 07:55 AM
like below fixes the issue As I mentioned in the comments use the error checking to do a mass conversion but if you still insist on a formula then here it is.

How can I find the amount of decimal places of a number from a list of numbers in a text file

Tag : python , By : Robin Buitenhuis
Date : March 29 2020, 07:55 AM
wish help you to fix your issue A text file has the following numbers: 1,2,3.02, 3.234,2.52 , Suppose the input file is something like below.
res = []
with open('input.txt') as file:
    number_list = file.readline().strip().split(',')
    for num in number_list:
        sig_fig = 0
        if '.' in number:
            sig_fig = len(number.split('.')[-1])
def get_sig_fig(num):
    return len(num.split('.')[-1]) if '.' in num else 0

with open('input.txt') as file:
    number_list = file.readline().strip().split(',')
    res = list(map(get_sig_fig, number_list))

Generate a list of unique random numbers where the number should not be same as index of number in list using kdb

Tag : development , By : Tony Z
Date : March 29 2020, 07:55 AM
will be helpful for those in need There are probably a few ways to do go about this. I came up with this:
q){$[any (r:neg[x]?x)=til x;.z.s x;r]}5
3 2 4 0 1
q){$[any (r:neg[x]?x)=til x;.z.s x;r]}5
2 0 4 1 3

Use a while loop to read in the entire text file and output a message a list with only the even numbers from the file to

Tag : chash , By : ganok_tor
Date : March 29 2020, 07:55 AM
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