python, print intermediate values while loop

python, print intermediate values while loop

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python, print intermediate values while loop
Tag : python , By : user177837
Date : November 27 2020, 03:01 PM

To fix this issue You didn't indent the x.append. So the code is not inside the loop and only the last value is appended to x. Correct would be:
while i <=N:
    i += 1
    xn = ((1 + (p/100))**i)*x0

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python loop only print values once

Tag : python , By : TBG
Date : March 29 2020, 07:55 AM
this one helps. I think you have the idea right in the if measurement < 500: condition, printing "light" only when last was different. You just have to repeat similar logic in the > 500 condition. But the real problem is that last here is a local variable, so the value will get reset to 9 on every call. So you need to remove the last=9, and define last outside of the function and declare it as global inside the function:
#in main program
last = 9
def RCTime ...:
    global last

MXNet print intermediate symbol values

Tag : python , By : Tornike
Date : March 29 2020, 07:55 AM
seems to work fine How do i find the actual numerical values held in an MXNet symbol. , After looking around a bit, I found you can do this by:
x = mx.sym.Variable('x')
y = mx.sym.Variable('y')
z = x + y
executor = z.bind(mx.cpu(), {'x': mx.nd.array([100,200]), 'y':mx.nd.array([300,400])})
output = executor.forward()
[<NDArray 2 @cpu(0)>]
print output[0].asnumpy()
array([ 400.,  600.], dtype=float32)

how do i print 6 values per line using the while loop statement in python

Tag : python , By : billputer
Date : March 29 2020, 07:55 AM
like below fixes the issue here's my code. i need some help in figuring out the print function. , In python, there is always a short way to do something :
arr = [format(x, '7d') for x in range(40, 999, 40)]
print('\n'.join(''.join(arr[i:i+6]) for i in range(0, len(arr), 6)))
 40     80    120    160    200    240
280    320    360    400    440    480
520    560    600    640    680    720
760    800    840    880    920    960

Functional way to convert a loop that is based on intermediate value that updates on each loop in python

Tag : python , By : PeteFilicetti
Date : March 29 2020, 07:55 AM
around this issue Not dwelling on why you want to do this, there are at least two different approaches to this. It very much depends on whether you want the call to be a tail call (which allows for the compiler to optimize away the function call in many strict functional languages - though not Python) or if you want a more straight forward recursive function.
The straight forward implementation is
import numpy as np

def recursive(rs, n_extra_pos, irrel_pos):
    if n_extra_pos == []:
        return [], irrel_pos
    extra_pos, irrel_pos = recursive(rs, n_extra_pos[:-1], irrel_pos)
    sample = set(rs.choice(list(irrel_pos), n_extra_pos[-1], replace=False))
    return extra_pos + [sample], irrel_pos - sample

irrel_pos = set(range(3, 11))
n_extra_pos = [2, 3]
rs = np.random.RandomState(1)
extra_pos, irrel_pos = recursive(rs, n_extra_pos, irrel_pos)
print(extra_pos, irrel_pos)
import numpy as np

def tail_recursive(rs, n_extra_pos, extra_pos, irrel_pos):
    if n_extra_pos == []:
        return extra_pos, irrel_pos
    sample = set(rs.choice(list(irrel_pos), n_extra_pos[0], replace=False))
    return tail_recursive(rs, n_extra_pos[1:], 
                          extra_pos + [sample], irrel_pos - sample)

irrel_pos = set(range(3, 11))
n_extra_pos = [2, 3]
rs = np.random.RandomState(1)
extra_pos, irrel_pos = tail_recursive(rs, n_extra_pos, [], irrel_pos)
print(extra_pos, irrel_pos)

Loop over list in Angular and print intermediate heading, reusing structure

Tag : angularjs , By : tlync
Date : March 29 2020, 07:55 AM
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