Displaying multiple colors on a single data bar

Displaying multiple colors on a single data bar

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Displaying multiple colors on a single data bar
Tag : development , By : user96271
Date : November 27 2020, 03:01 PM

I wish this helpful for you Right click on your column group and insert 'inside group'.
Drag and drop a Data Bar into your new cell.

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Displaying data from multiple entities in a single NSTableView (Core-Data)

Tag : cocoa , By : Antony Briggs
Date : March 29 2020, 07:55 AM
like below fixes the issue You can do this assuming that you have set the reverse relationship for pupilID (i.e. a relationship from Pupil to the Loan). If you call that relationship loan, and have an NSArrayController, PupilsController bound to the collection of Pupils, then your first table could be bound to PupilsController.arrangedObjects.loan.loadID and your other columns bound as you'd expect.
On a purely stylistic side note, the pupilID property would more appropriately be named pupil. Core Data is no an ORM and you're not in SQL JOIN land any more. Name the properties what they are, not how they're implemented under the hood by Core Data.

Singleseries bar displaying multiple colors on the basis of given data in a Barchart uding achartengine lib

Tag : android , By : Kyle
Date : March 29 2020, 07:55 AM
will be helpful for those in need Different colors for single series(or elements of same series) is not yet implemented or provided by the Achartengine library... :
But there are methods using multiple series or Stacked bar graph
   int[] expense = {50, 75, 100, 125, 150, 175, 200, 225 };
  static ArrayList<Integer> series1 = new ArrayList<Integer>();
  static ArrayList<Integer> series2 = new ArrayList<Integer>();
  static ArrayList<Integer> series3 = new ArrayList<Integer>();
for(int i=0;i<expense.lenght;i++)
  if(expense[i]> 50 & expense[i]<100)
   { series1.add(expense[i]);

if(expense[i]> 100 & expense[i]<150)

Highchart Color Issue for series with single data with multiple colors

Tag : javascript , By : Puneet Madaan
Date : March 29 2020, 07:55 AM
Hope this helps Another solution is to set array of colors for series, then set colorByPoint: true, see: http://jsfiddle.net/7VNwk/2/
        series: [{
            type: 'column',
            name: 'Vengadesh',
            data: [2, 2, 2],
            colors: ['blue', 'red', 'green'],
            colorByPoint: true


Displaying multiple users from http data instead of a single user

Tag : javascript , By : Andrew Bailey
Date : March 29 2020, 07:55 AM
With these it helps You should do one request for multiple users, then iterate over them:
Get all users:
// rather than getting just user 1
const users$ = sources.HTTP // users (plural)
.filter(res$ => res$.request.url.indexOf(USERS_URL) === 0)
.map(res => res.body)
.startWith([]); // start with an empty array
users.map(user => 
  div('.user-details', [
    h1('.user-name', user.name),
    h4('.user-email', user.email),
    a('.user-website', {href: user.website}, user.website)
function main(sources) {
  const USERS_URL = 'http://jsonplaceholder.typicode.com/users/';
  const getAllUsers$ = sources.DOM.select('.get-all').events('click')
    .map(() => {
      return {
        url: USERS_URL,
        method: 'GET'

  const users$ = sources.HTTP
    .filter(res$ => res$.request.url.indexOf(USERS_URL) === 0)
    .map(res => res.body)

  const vtree$ = users$.map(users => {
    return div('.users', [
      button('.get-all', 'Get all users'),
      ...users.map(user => 
        div('.user-details', [
          h1('.user-name', user.name),
          h4('.user-email', user.email),
          a('.user-website', {href: user.website}, user.website)

  return {
    DOM: vtree$,
    HTTP: getAllUsers$

Androidmpchart piechart not displaying single color but displaying colors when more than one

Tag : android , By : user147496
Date : March 29 2020, 07:55 AM
To fix this issue Change your compile dependency to compile 'com.github.PhilJay:MPAndroidChart:v2.2.4' I tried your code with that version of MpAndroidChart and it worked perfectly, when I changed to the version you used, same it produced the error you have.
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