How to write a grep regular expression such that a certain string does not appear anywhere before the matching pattern o
Tag : regex , By : drbillll
Date : March 29 2020, 07:55 AM
Any of those help I am trying to find all instances of statements like grep -nrE "^[^']+\.Transaction"
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How do I grep this pattern with regular-expression in shell?
Tag : regex , By : TheMoo
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further I want to grep the pattern like "1-10","10-20","1-9"(without double quotes) with the following code: , The minus needs no masking. + allows multiple occurrences. egrep '[0-9]+-[0-9]+' mydoc
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Perl regular expression to grep for a word after specific pattern
Tag : regex , By : Nate Bedortha
Date : March 29 2020, 07:55 AM
seems to work fine A simple capture might suit your needs. Though it is fairly unclear what you mean. my ($word) = $string =~ /\Q[ some contents ] NAME:saranyya \E(.+)/;
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Regular Expression pattern issue
Tag : chash , By : Priyatna Harun
Date : March 29 2020, 07:55 AM
wish help you to fix your issue In C#, you don't need to delimit regex patterns with / characters. Try this: Regex rex = new Regex("[^a-zA-Z0-9]+");
Response.Write(rex.Replace("asd123!-<>@;',.", ""));
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How to find a pattern in text with Regular Expression (Extended), grep and Bash
Tag : regex , By : CSCI GOIN KILL ME
Date : March 29 2020, 07:55 AM
Any of those help If you want to match 1 or more alphanuemric or *, ., + symbols inside (...), you may use grep -E "\( *[a-zA-Z0-9*.+]+ *\)"
grep -E "\( *[a-zA-Z0-9*.+] *\)"
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