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How can I use regex in python so that characters not included are disallowed?


How can I use regex in python so that characters not included are disallowed?

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How can I use regex in python so that characters not included are disallowed?
Tag : python , By : Mena
Date : November 27 2020, 03:01 PM

Hope that helps The semantic error is that you keep overwriting the content of valid even when there has been no match on the character before.
Avoid the for loop altogether and change the regex to "[A-Za-z0-9!£$%^&*]+$"

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Regex: dealing with unpredictable inputs: disallowed trailing (but otherwise OK) characters


Tag : python , By : hlpimfalling
Date : March 29 2020, 07:55 AM
wish of those help I'm trying to write a regex that parses - . The problem is that the inputs are a little unpredictable and the formatting of allowed tickers is broad. , You probably want something like this:
/[a-z](?:[a-z.-]*[a-z])?/i

What characters would be included in regex range a-Z?


Tag : regex , By : CyberGreg
Date : March 29 2020, 07:55 AM
I hope this helps . The range [0-Z] is valid, depending on the regex engine [a-Z] will either be invalid or it will be a range that can't match any characters. In a character class range the start and end characters are just code points and all characters between those code points will be included in the range.
In the case of [0-Z], this is equivalent to the following more readable character class:
[0-9:;<=>?@A-Z]

Regex: replace all between two characters where no comma is included


Tag : javascript , By : ianium
Date : March 29 2020, 07:55 AM
I hope this helps you . You started out right, but complicated everything. Simply:
\+[^,]+\+

Regex to determine if one string is included in another (n characters)


Tag : regex , By : Ganesh
Date : March 29 2020, 07:55 AM
hop of those help? Lest say that the password length always >4 char, we can take the first 4 char from the old pass and then compare it every 4 next char until the end of oldpassword length.
Boolean found = false;
int l = 0, r = 4;
while( found == false && r <= oldpass.length()){
    String tmp = oldpass.substring(l,r);
    found = newpass.contains(tmp);
    l++; r++;
}

Python regex disallowed characters still accepted?


Tag : python , By : unadopted
Date : March 29 2020, 07:55 AM
Hope that helps There are four mistakes here:
you swapped valid and not valid: so you write to the screen that the username is invalid in case re.search(..) succeeds; you do not ask the user to enter a new username; you break even in case the string has invalid characters; your regex looks for a sequence 'abcd...' (so an 'a' followed by a 'b', etc.).
while b == 0:
    username = input("Enter a username: ")
    if len(username) < 6 or len(username) > 16:
        print("Incorrect length, try again.")
    else:
        if not re.search(a, username):
            print("Invalid characters entered, try again")
        else:
            print("Username accepted")
            break
[a-z0-9A-Z!£&*@#_=+-]
[a-z0-9A-Z!£&*@#_=+-]*
^[a-z0-9A-Z!£&*@#_=+-]*$
a = '^[a-z0-9A-Z!£&*@#_=+-]*$'
b = 0
while b == 0:
    username = input("Enter a username: ")
    if len(username) < 6 or len(username) > 16:
        print("Incorrect length, try again.")
    else:
        if not re.search(a, username):
            print("Invalid characters entered, try again")
        else:
            print("Username accepted")
            break
a = '^[a-z0-9A-Z!£&*@#_=+-]*$'

while True:
    username = input("Enter a username: ")
    if not 6 <= len(username) <= 16:
        print("Incorrect length, try again.")
    elif not re.search(a, username):
        print("Invalid characters entered, try again")
    else:
        print("Username accepted")
        break
Enter a username: f
Incorrect length, try again.
Enter a username: blablablablablablablabla
Incorrect length, try again.
Enter a username: foobar<>~~
Invalid characters entered, try again
Enter a username: fooba
Incorrect length, try again.
Enter a username: foobar
Username accepted
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