Regex: dealing with unpredictable inputs: disallowed trailing (but otherwise OK) characters
Tag : python , By : hlpimfalling
Date : March 29 2020, 07:55 AM
wish of those help I'm trying to write a regex that parses - . The problem is that the inputs are a little unpredictable and the formatting of allowed tickers is broad. , You probably want something like this:/[a-z](?:[a-z.-]*[a-z])?/i
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What characters would be included in regex range a-Z?
Tag : regex , By : CyberGreg
Date : March 29 2020, 07:55 AM
I hope this helps . The range [0-Z] is valid, depending on the regex engine [a-Z] will either be invalid or it will be a range that can't match any characters. In a character class range the start and end characters are just code points and all characters between those code points will be included in the range. In the case of [0-Z], this is equivalent to the following more readable character class: [0-9:;<=>?@A-Z]
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Regex: replace all between two characters where no comma is included
Date : March 29 2020, 07:55 AM
I hope this helps you . You started out right, but complicated everything. Simply: \+[^,]+\+
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Regex to determine if one string is included in another (n characters)
Tag : regex , By : Ganesh
Date : March 29 2020, 07:55 AM
hop of those help? Lest say that the password length always >4 char, we can take the first 4 char from the old pass and then compare it every 4 next char until the end of oldpassword length. Boolean found = false;
int l = 0, r = 4;
while( found == false && r <= oldpass.length()){
String tmp = oldpass.substring(l,r);
found = newpass.contains(tmp);
l++; r++;
}
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Python regex disallowed characters still accepted?
Date : March 29 2020, 07:55 AM
Hope that helps There are four mistakes here: you swapped valid and not valid: so you write to the screen that the username is invalid in case re.search(..) succeeds; you do not ask the user to enter a new username; you break even in case the string has invalid characters; your regex looks for a sequence 'abcd...' (so an 'a' followed by a 'b', etc.). while b == 0:
username = input("Enter a username: ")
if len(username) < 6 or len(username) > 16:
print("Incorrect length, try again.")
else:
if not re.search(a, username):
print("Invalid characters entered, try again")
else:
print("Username accepted")
break
[a-z0-9A-Z!£&*@#_=+-]
[a-z0-9A-Z!£&*@#_=+-]*
^[a-z0-9A-Z!£&*@#_=+-]*$
a = '^[a-z0-9A-Z!£&*@#_=+-]*$'
b = 0
while b == 0:
username = input("Enter a username: ")
if len(username) < 6 or len(username) > 16:
print("Incorrect length, try again.")
else:
if not re.search(a, username):
print("Invalid characters entered, try again")
else:
print("Username accepted")
break
a = '^[a-z0-9A-Z!£&*@#_=+-]*$'
while True:
username = input("Enter a username: ")
if not 6 <= len(username) <= 16:
print("Incorrect length, try again.")
elif not re.search(a, username):
print("Invalid characters entered, try again")
else:
print("Username accepted")
break
Enter a username: f
Incorrect length, try again.
Enter a username: blablablablablablablabla
Incorrect length, try again.
Enter a username: foobar<>~~
Invalid characters entered, try again
Enter a username: fooba
Incorrect length, try again.
Enter a username: foobar
Username accepted
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