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Get sums grouped by date by same column filtered by 2 conditions


Get sums grouped by date by same column filtered by 2 conditions

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Get sums grouped by date by same column filtered by 2 conditions
Tag : python , By : lhoBas
Date : November 27 2020, 03:01 PM

wish helps you Use replace for numeric first and then groupby with aggregate sum, then reshape by unstack:
#or use parameter decimal=',' to read_csv
df['amount_USD'] = df['amount_USD'].replace(',','.', regex=True).astype(float)

df = df.groupby(['transaction_date','transaction_status'])['amount_USD']
       .sum()
       .unstack(fill_value=0)
print (df)
transaction_status  CHARGED  DECLINED
transaction_date                     
2015-07-29             0.00     10.96
2015-08-11            21.57     14.70
df = df.pivot_table(index='transaction_date',
                    columns='transaction_status', 
                    values='amount_USD', 
                    aggfunc='sum', 
                    fill_value=0)
print (df)

transaction_status  CHARGED  DECLINED
transaction_date                     
2015-07-29             0.00     10.96
2015-08-11            21.57     14.70
df = df.reset_index().rename_axis(None, axis=1)
print (df)
  transaction_date  CHARGED  DECLINED
0       2015-07-29     0.00     10.96
1       2015-08-11    21.57     14.70

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get result filtered by count grouped by date in cakephp 3


Tag : cakephp , By : wpoch
Date : March 29 2020, 07:55 AM
I hope this helps you . You're nearly there, you need to use a HAVING clause, WHERE won't work here, as it works on single results, rather than on aggregated ones, which is what you need here.
SQL functions can be built using the function builder, and in order to create a comparison with a function expression, you'll have to leavarege the expression builder, using for example the lt() (less than) method.
$this
    ->find()
    ->select(['CustomApi.id', 'CustomApi.api_key'])
    ->leftJoinWith('ApiCalls', function ($q) {
        return $q->where(['ApiCalls.created' => date('Y-m-d')]);
    })
    ->group('CustomApi.id')
    ->having(function ($exp, $q) {
        return $exp->lt(
            $q->func()->count('ApiCalls.id'),
            100
        );
    });

SQL - How can I sum up a column after the results have been grouped and filtered in the having clause?


Tag : sql , By : ZsA
Date : March 29 2020, 07:55 AM
will be helpful for those in need Here is my current query: The objective is to find accounts that have received at least $500 in deposits within 30 days of their first deposit. Some accounts have been closed and re-opened, hence the first line of the 'WHERE' clause. , You can try something like that:
select      filtered.accountNumber,
            min(filtered.transDate) as "first deposit",
            filtered.transDate,
            CAST(DATEADD(d,30,min(filtered.transDate)) as date) as "30 days",
            sum(filtered.amount) as "sum",
            filtered.amount,
            filtered.accountOpenDate
from        
(
    select * from Deposits
    inner join  Members on Deposits.accountNumber = members.accountNumber 
    where       Deposits.transDate >= members.accountOpenDate
    and         Deposits.accountNumber = 123456
    having      Deposits.transDate between min(Deposits.transDate) and DATEADD('d',30,min(Deposits.transDate))
) as filtered
group by    filtered.accountNumber 
having sum(filtered.amount) >= 500

Sums of points per date grouped by additional column in a form of a list


Tag : python , By : Alpinfish
Date : March 29 2020, 07:55 AM
Hope that helps I would like to obtain sum of points of some technologies per date from pandas data frame. A reproducible example: , We can convert your original data to this format
s=data.tech.str.len()
newdf=pd.DataFrame({'date':data.date.repeat(s),'score':data.score.repeat(s),'tech':np.concatenate(data.tech.values)})
newdf
Out[477]: 
         date  score    tech
0  2017-01-31      1     c++
0  2017-01-31      1  python
1  2017-02-28      4     c++
1  2017-02-28      4       c
1  2017-02-28      4    java
2  2017-02-28      2    java
pd.pivot_table(newdf,index='date',columns='tech',values='score',aggfunc='sum',fill_value=0)
Out[476]: 
tech        c  c++  java  python
date                            
2017-01-31  0    1     0       1
2017-02-28  4    4     6       0

Subtraction SUMs of values in first column (Amount) grouped by another second column (Products) with condition in anothe


Tag : sql , By : Ashaea
Date : March 29 2020, 07:55 AM
This might help you Because some Product may be or may not in some Process, first we must collect all the valid Products and only then calculate the result Here the code I've just tested on your data:
with all_prod as (select distinct Product from t1)
select  
  ap.Product, coalesce(B.Amount,0) - coalesce(A.Amount,0) Amount
  from all_prod ap
  left join (
  select SUM(Amount) Amount, Product, 2 Process 
    from t1 
    where Process = 2
    group by Product, Process) A on A.Product = ap.Product
  left join (
  select SUM(Amount) Amount, Product, 2 Process 
    from t1 
    where Process = 1
    group by Product, Process) B on ap.Product = B.Product 

Cumulative sum on different columns grouped by date and filtered differently


Tag : powerbi , By : orlandoferrer
Date : March 29 2020, 07:55 AM
I wish this help you This is a classic example of a Cumulative Sum DAX Pattern.
You do not need separate tables.
a_cum = 
VAR CurrentID = [id]
RETURN
    CALCULATE (
        SUM ( Table01[a] ),
        FILTER (
            ALLEXCEPT ( Table01, Table01[dte] ),
            Table01[id] <= CurrentID
        )
    )
b_cum = 
VAR CurrentID = [id]
RETURN
    CALCULATE (
        SUM ( Table01[b] ),
        FILTER (
            ALLEXCEPT ( Table01, Table01[dte] ),
            Table01[id] >= CurrentID
        )
    )
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