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Flask doesn't stream on Lambda


Flask doesn't stream on Lambda

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Flask doesn't stream on Lambda
Tag : python , By : Dmitry
Date : November 26 2020, 03:01 PM

I think the issue was by ths following , If I understand your question correctly, the issue is related to the design of the services -- specifically, the interfaces they expose.
Both API Gateway and AWS Lambda use an en bloc request-response model for their interactions.

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Java 8 lambda: iterate over stream objects and use previous/next object(s) in stream


Tag : java , By : Nate Bedortha
Date : March 29 2020, 07:55 AM
wish helps you Sometimes, attempting to do everything with lambda expressions makes solutions more complicated. You can use:
messages.stream()
    .mapToLong(Message::getOffset)
    .sorted()
    .forEachOrdered(new LongConsumer() {
        boolean first=true;
        long expected;
        public void accept(long value) {
            if(first) first=false;
            else if(value!=expected)
                LOG.error("Missing offset(s) found in messages: missing from {} to {}",
                          expected, value);
            expected=value+1;
        }
    });
long[] l = messages.stream().mapToLong(Message::getOffset).toArray();
Arrays.sort(l);
for(int ix=1; ix<l.length; ix++) {
    long value = l[ix], expected = l[ix-1]+1;
    if(value!=expected)
        LOG.error("Missing offset(s) found in messages: missing from {} to {}",
                  expected, value);
}
OptionalLong optMin = messages.stream().mapToLong(Message::getOffset).min();
if(!optMin.isPresent()) return;
long min = optMin.getAsLong();
BitSet bset = messages.stream()
    .mapToLong(Message::getOffset)
    .collect(BitSet::new, (bs,l) -> bs.set((int)(l-min)), BitSet::or);
for(int set=0, clear; set>=0; ) {
    clear = bset.nextClearBit(set);
    set = bset.nextSetBit(clear);
    if(set >= 0)
        LOG.error("Missing offset(s) found in messages: missing from {} to {}",
                  min+clear, min+set);
}
LongSummaryStatistics stat = messages.stream()
    .mapToLong(Message::getOffset).summaryStatistics();
if(stat.getCount()==0 ||
   // all solutions assume that there are no duplicates, in this case,
   // the following test allows to prove that there are no gaps:
   stat.getMax()-stat.getMin()==messages.size()-1) {
    return;
}

if(stat.getMax()-stat.getMin()>Integer.MAX_VALUE) {
    // proceed with array based test
    …
}
else {
    long min = stat.getMin();
    // proceed with BitSet based test
    …

replace statement lambda with regular expression Lambda java 8 stream map


Tag : development , By : merten
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , I have this map function as part of my stream. parse.apply is basically doing Double::valueOf. My intelliJ suggest me I can replace statement lambda with regular expression Lambda. , You can filter out all empty strings before reaching .map:
.filter(s -> !StringUtils.isEmpty(s))
.map(parse)
.map(s -> StringUtils.isEmpty(s) ? "0": s)
.map(parse)

Convert Stream<Stream<T>> to T[][] with Streams/Lambda's in Java


Tag : java , By : user91848
Date : March 29 2020, 07:55 AM
I wish this help you I am looking to see if there was a better way to solve my dilemma having to use these signatures (note: the T[][] is required because of Spock testing and I am providing T[][] as a data provider) , You can use Array.newInstance like this:
public static <T> T[][] createArrays(Class<T> clazz, T... items) {
    Stream<Stream<T>> streams = EnumPerm.of(items);
    return streams
        .map(s -> s.toArray(len -> (T[])Array.newInstance(clazz, len)))
        .toArray(len -> (T[][])Array.newInstance(items.getClass(), len));
}
public static <T> T[][] createArrays(Class<T> clazz, T... items) {
    Stream<Stream<T>> streams = EnumPerm.of(items);
    T[] template = Arrays.copyOf(items, 0);
    return streams
        .map(s -> s.toArray(len -> Arrays.copyOf(template, len)))
        .toArray(len -> (T[][])Array.newInstance(template.getClass(), len));
}
public static <T> T[][] createArrays(Class<T> clazz, T... items) {
    Stream<Stream<T>> streams = EnumPerm.of(items);
    return streams
        .map(s -> s.toArray(len -> (T[])Array.newInstance(clazz, len)))
        .toArray(len -> (T[][])Array.newInstance(clazz, len, 0));
}

AWS Lambda + Kinesis : from what position in the stream do lambda functions restart?


Tag : amazon-web-services , By : user133629
Date : March 29 2020, 07:55 AM

Should I care about dynamodb stream shards if I process stream events by lambda?


Tag : java , By : user130518
Date : March 29 2020, 07:55 AM
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