CodeFights Interview Practice- Dynamic Programing : Basic : fillingBlocks

Hope that helps In order to use the MemoryWrite macro I had to convert 0x80001000 to 2147487744. I think this is bad practice and unclear. Is there a way that I could do this just using the hex value?

#define FLAG 0x80001000u

To fix the issue you can do As @Graipher mentioned in the comments, this is certainly valid in some cases, but in your particular case, it is unnecessary. If your function depends on a local variable, then you're returning a closure that needs to be reconstructed every time you call the method. But in your case, the function is going to behave the same way every time you call the method, so it would make more sense to define it globally as a private method, or even as a lambda in your case.

ver = lambda x: x if x else 'null'

def _ver(string):
    ...