Pass variable in API url in java .

Pass variable in API url in java .

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Pass variable in API url in java .
Tag : java , By : Erwin
Date : November 25 2020, 03:01 PM

it fixes the issue Use String concatenation (with the + operator) to combine String literals and variables:
String url = "https://"+hostname+":"+port+"/api/scanCluster?cid="+cluster+"&mode=1";

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How do i pass java script variable into java code snippet in jsp page

Tag : java , By : user181945
Date : March 29 2020, 07:55 AM
hop of those help? I want to redirect the user into last accessed page after session expire and i prompt user to login again. In that i passed last page url into one parameter and invoke a seesioerror action for validate the user. , You should be using

jQuery / Colorbox - Pass one java variable to PHP variable in popup

Tag : javascript , By : Vodkat
Date : March 29 2020, 07:55 AM
will be helpful for those in need Will you please please tell me how to get java variable "data_id" value in PHP Variable "$gal_id" i m not able pass the value of java variable into PHP Variable so please also let me know if you find the solution , try this edit... I have integrated ajax with your code
<script type="text/javascript">
   var data_id = $(this).data('id');
         type: "GET",
         url: "ajax.php?gal_id="+data_id,
         success: function(data) {

<div style='display:none'>
    <div id='inline_content'>
    <span id="idvalue"></span>
<span id="images"></span>

//whatever content you will echo here will be send to the main page and put to #images span tag...
//put your connection string here.. to connect the database
        $gal_id = $_GET['gal_id']; 
        $check = mysql_query("select * from img where id = '$gal_id'");
        while ($run = mysql_fetch_array($check)){


java match string to variable name and pass the variable's value

Tag : java , By : user122937
Date : March 29 2020, 07:55 AM
I wish did fix the issue. You can create a map with variable names as keys and the desired argument to be passed to pollVisible function as the value. So your map would look something like :
myMap : name -> field_ID_Name

Java pass variable to class return different variable

Tag : java , By : smbrant
Date : March 29 2020, 07:55 AM
wish of those help Welcome to programming. One thing to think about here is it seems that you think your Secondary class is an entity that is immutable and runs alongside your program. It isn't. You're creating an object that contains data and functionality that you want to use elsewhere in your program.
Your Secondary object can be instantiated and then used to perform tasks. You could also do this from another method created inside of your base class, but that would have to be static as well.
import java.util.*;
import java.io.*;

public class Primary {
   public static void main(String[] args) throws Exception {
      String clearText = ("");

      // Collect user input
      System.out.print("Type Text");
      clearText = scnr.next();

      // Create hash and display
      String hashText = HashService.generateHash(clearText);

public class HashService {
  public static String generateHash(String fromText){
    // implementation here
    return null;
import java.util.*;
import java.io.*;

public class Primary {
   public static void main(String[] args) throws Exception {
      String clearText = ("");

      // Collect user input
      System.out.print("Type Text");
      clearText = scnr.next();

      // Create hash and display
      HashedPassword hash = new HashedPassword(clearText);
      String hashText = hash.getHashedPW();

public class HashedPassword {
  private String hashedPW = ""
  public HashedPassword(String fromText){
    // Assign hashedPW with some logic
    hashedPW = fromText;

  public getHashedPW(){
    return hashedPW;

What is the rule in Java for 'pass by reference' / 'pass by value' for variable assignment?

Tag : java , By : Al Dimond
Date : March 29 2020, 07:55 AM
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