Print a list in reverse order with range()?
Tag : python , By : Carlos Galdino
Date : March 29 2020, 07:55 AM
To fix this issue How can you produce the following list with range() in Python? , use reversed() function: reversed(range(10))
list(reversed(range(10)))
range(5, -1, -1)
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How to traverse a list in reverse order in Python (index-style: '... in range(...)' only)
Tag : python , By : Bimal Poudel
Date : March 29 2020, 07:55 AM
around this issue Avoid looping with range, just iterate with a for loop as a general advice. If you want to reverse a list, use reversed(my_list). my_list = reversed([array0,array1,array2,array3])
my_list = reversed([array0,array1,array2,array3])[:-1]
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Why does the list.reverse() function reverse an unspecified list in addition to the specified one?
Date : March 29 2020, 07:55 AM
should help you out In Python, as in many other OO languages, lists are assigned by reference. Thus, when you do: word_list_reversed = word_list from copy import copy
word_list_reversed = copy(word_list)
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Error: IndexError: string index out of range. Trying to reverse the order of a list
Date : March 29 2020, 07:55 AM
Does that help I'm working on a problem in 'Python for Everyone', chapter 7. The program is meant to take a file and reproduce that file in reverse order of characters. This code makes a list of the characters as they appear, but when I use: , I don't get why you want to sort, you can simply use: reversedList = charList[::-1]
sorted(charList, key=charList.index, reverse=True)
reversedList = []
for i in range(len(charList)-1,-1,-1):
reversedList.append(charList[i])
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reverse range vs normal range when trying to remove items from a list using a for loop
Date : March 29 2020, 07:55 AM
I wish this helpful for you As DYZ said in comments, with reverse indexing, you're changing the indices of items that you have already processed, so the code won't fail when it continues. However, it seems you're lucky with the input, since you're deleting two items at once. If you change the input list to this one, it will still fail with an IndexError. lst = ['EAST', 'EAST', 'NORTH', 'SOUTH']
num = 0
while num < len(lst) - 1:
if lst[num] == 'NORTH' and lst[num + 1] == 'SOUTH':
del lst[num]
del lst[num - 1]
else:
num += 1
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