Sum up the second value from one dictionary with all values from another dictionary

Sum up the second value from one dictionary with all values from another dictionary

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Sum up the second value from one dictionary with all values from another dictionary
Tag : python , By : Brandon
Date : November 25 2020, 03:01 PM

seems to work fine I have two dictionaries, with the same keys, but different values. I want to make a new dictionary with all values from dictionary1 to be summed up with the second value of dictionary2. , I solved it. For future if anyone needs the answer, this did the job:
for key in dic1:
    for i in range(0,len(dic1[key])):
        if len(dic1[key]) > 0:
            dic1[key][i] = dic1[key][i] + dic2[key][1]
dic3[key][i] = dic1[key][i] + dic2[key][1]

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C# Sum of Values in a nested dictionary where value is a class Dictionary<string, Dictionary<Int16, CommonData>

Tag : chash , By : demize95
Date : March 29 2020, 07:55 AM
I hope this helps . You didn't give some example input/output but I think your looking for something like
var result = yourMainDict.OrderBy(x => x.Value.Sum(v => v.Value.Delivered + v.Value.Submitted + v.Value.Failed));

How to replace dictionary values which is dictionary with tuple for each dictionary in list

Tag : python , By : Sascha Brossmann
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , , This isn't working because when you do:
D = [dictionary for i in range(10)]
i['c'] = tuple(i['c'].items())
In [10]: dictionary = { "a" : "100", "b" : "200", "c" : {"a":"f","b":"4"} }
    ...: D = [dictionary for i in range(10)]
    ...: print([hex(id(x)) for x in D])
['0x105c59088', '0x105c59088', '0x105c59088', '0x105c59088', '0x105c59088', '0x105c59088', '0x105c59088', '0x105c59088', '0x105c59088', '0x105c59088']
In [11]: dictionary = { "a" : "100", "b" : "200", "c" : {"a":"f","b":"4"} }
    ...: D = [dictionary.copy() for i in range(10)]
    ...: print([hex(id(x)) for x in D])
['0x105c592c8', '0x105c59e48', '0x105cfd848', '0x105c9af48', '0x105d06c48', '0x105c59708', '0x105d06cc8', '0x105c59488', '0x105c59e08', '0x105c593c8']
In [12]: for i in D:
    ...:     i['c'] = tuple(i['c'].items())

In [13]: D
[{'a': '100', 'b': '200', 'c': (('b', '4'), ('a', 'f'))},
 {'a': '100', 'b': '200', 'c': (('b', '4'), ('a', 'f'))},
 {'a': '100', 'b': '200', 'c': (('b', '4'), ('a', 'f'))},
 {'a': '100', 'b': '200', 'c': (('b', '4'), ('a', 'f'))},
 {'a': '100', 'b': '200', 'c': (('b', '4'), ('a', 'f'))},
 {'a': '100', 'b': '200', 'c': (('b', '4'), ('a', 'f'))},
 {'a': '100', 'b': '200', 'c': (('b', '4'), ('a', 'f'))},
 {'a': '100', 'b': '200', 'c': (('b', '4'), ('a', 'f'))},
 {'a': '100', 'b': '200', 'c': (('b', '4'), ('a', 'f'))},
 {'a': '100', 'b': '200', 'c': (('b', '4'), ('a', 'f'))}]

In python, I want to sort a dictionary based on the dictionary of dictionary values

Tag : python , By : Chris Lomax
Date : March 29 2020, 07:55 AM
help you fix your problem In python I have a dictionary of dictionary such as , You can use a custom key for sorting:
print(dict(sorted(my_dict.items(), key=lambda x: x[1]['mark3'], reverse=True)))
{'C': {'mark1': '11', 'mark2': '19', 'mark3': '25'}, 'A': {'mark1': '15', 'mark2': '12', 'mark3': '20'}, 'B': {'mark1': '10', 'mark2': '90', 'mark3': '14'}}
from collections import OrderedDict
my_dict = OrderedDict([('A', {'mark1': '15', 'mark2': '12', 'mark3': '20'}), ('B', {'mark1': '10', 'mark2': '90', 'mark3': '14'}), ('C', {'mark1': '11', 'mark2': '19', 'mark3': '25'})])
print(OrderedDict(sorted(my_dict.items(), key=lambda x: x[1]['mark3'], reverse=True)))
print(dict(sorted(my_dict.items(), key=lambda x: (x[1]['mark3'], x[1]['mark2']), reverse=True)))

Replacing the keys of a dictionary with values of another dictionary to create a new dictionary

Tag : python , By : Cenneca
Date : March 29 2020, 07:55 AM
hope this fix your issue Your attempts rewrite the data at each iteration. Plus they lose the relation between the name and the index by only iterating on the values. Time to rethink the approach from scratch.
I would combine both dict data and build a new dictionary using dictionary comprehension:
result = {name:ages[index] for index,name in d1.items()}

>>> result
{'Bill': 20, 'Bob': 40, 'Callum': 20, 'Herrera': 21, 'Liz': 19}
result = {name:ages.get(index,"unknown") for index,name in d1.items()}

How to modify or create a dictionary based on one dictionary querying the values of another dictionary in Python

Tag : python , By : Martin
Date : March 29 2020, 07:55 AM
I wish this helpful for you I have two dictionaries: Dictionary A has an increasing and unique Item ID as the key and it is associated to an FID value. , try this code:
dict_a = dict({11111: "FID01", 22222: "FID01", 33333:"FID03", 44444: "FID01"} )
dict_b = dict({"FID01": 25, "FID02": 50, "FID03": 75, "FID04": 90})

dict_b_keys = dict_b.keys()

{key: dict_b[value] for (key, value) in dict_a.items() if value in dict_b_keys}
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