Scanner input needed twice, when only wanted once

Scanner input needed twice, when only wanted once

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Scanner input needed twice, when only wanted once
Tag : java , By : Porta
Date : November 25 2020, 03:01 PM

I wish this help you You are not using the array int[] temperatures so you could remove the statement that insert in it...
If you really want to keep the value in an array. Simply use a Double[] temperatures then read your scanner.
fahrenheit = sc.nextDouble();
temperatures[i] = fahrenheit;

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difference between java.util.Scanner input = new Scanner () and import Scanner in main class

Tag : java , By : user105769
Date : November 22 2020, 11:05 AM
I wish this help you Both are same , if you have class names conflict ion you can use class with package name.

Scanner expects more input than is needed

Tag : java , By : user185939
Date : March 29 2020, 07:55 AM
Any of those help Your for loop should read the input once and remember it as mentioned. Otherwise each call to in.nextInt() will block until you enter another integer. Keeping close to your same code you need to do the following.
while (!good){
    if (!in.hasNextInt()){
        System.out.print("Sorry, you must enter a whole\nnumber between 1 and 6: ");
    } else {
        level = in.nextInt();
        if (level < 0 || level > 6) {
            System.out.print("Sorry, you must enter a whole\nnumber between 1 and 6: ");
        } else {
            good = true;

Scanner.nextLine(); called before wanted due to loop

Tag : java , By : user169463
Date : March 29 2020, 07:55 AM
hop of those help? Well, I found out a solution for your problem, I'm not sure why your problem is happening. Instead of using static Scanner input = new Scanner(System.in); in our Player class, create a new Scanner in every your gets*.
Here is a suggestion:
public static Player createPlayerFromConsole() {
    Scanner input = new Scanner(System.in);

    System.out.println("Enter your character's name.");
    String name = input.nextLine();

    System.out.println("Enter your character's stamina.");
    int stamina = input.nextInt();

    System.out.println("Enter your character's defense.");
    int defense = input.nextInt();

    System.out.println("Enter your character's strength.");
    int strength = input.nextInt();

    System.out.println("Enter your character's agility.");
    int agility = input.nextInt();

    System.out.println("Enter your character's intellect.");
    int intellect = input.nextInt();

    return new Player(name, stamina, defense, strength, agility, intellect);

Check, if String contains only needed characters. If no - input new String from Scanner

Tag : java , By : Roel van Dijk
Date : March 29 2020, 07:55 AM

How would I input Scanner scanner = new Scanner(System.in); for JOptionpane?

Tag : java , By : Dré
Date : March 29 2020, 07:55 AM
it fixes the issue It looks like you are confusing the console with dialog boxes. Scanner is used when getting input from the keyboard.
JOptionPane is used for a dialog box. if you want to get back input then you can write
String s = JOptionPane.showInputDialog("Enter anything");
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