Convert list to data frame

Convert list to data frame

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Convert list to data frame
Tag : r , By : boonchew
Date : November 24 2020, 03:01 PM

this one helps. You have line breaks in your website1 column. You could replace them with another character, for example with
df.res[,"website1"] <- gsub("\\n", "; ", df.res[,"website1"])

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Why does ifelse convert a data.frame to a list: ifelse(TRUE, data.frame(1), 0)) != data.frame(1)?

Tag : class , By : Tim Benninghoff
Date : March 29 2020, 07:55 AM
Does that help ifelse is generally intended for vectorized comparisons, and has side-effects such as these: as it says in ?ifelse,
‘ifelse’ returns a value with the same shape as ‘test’ ...
return(if (condition) mydf else NA)
if (!condition) mydf[] <- NA

how to convert a data frame with a list in the value to a big data frame with the each level as a single column value in

Tag : python , By : ezzze
Date : March 29 2020, 07:55 AM
With these it helps I have a data frame look like below: , Try this:
pd.DataFrame([{'col_A':row['col_A'], 'col_B':val} 
               for ind, row in df.iterrows()
               for val in row['col_B']])

R: Convert a data.frame into a list with tags from data.frame

Tag : r , By : cnemelka
Date : March 29 2020, 07:55 AM
this one helps. I have the following dataframe: , You can use apply function:
list0 <- setNames(apply(df0, 1, function(row) {
                 a <- list()
                 a[[row[2]]] <- as.numeric(row[3]) 
                 return (a) 
              }), df0$N1)
[1] 10

[1] 10

List of 2
 $ A:List of 1
  ..$ C: num 10
 $ B:List of 1
  ..$ C: num 10

How to convert list elements within a data frame to a data frame

Tag : r , By : Angelo Giannatos
Date : March 29 2020, 07:55 AM
Any of those help I have a data frame with some list items, and within that data frame I would like to convert all the list items to a data frame. The example data frame df. I want data frame without any list item. , You can use unlist to do what you need. I hope this is helpful.
unlisted <- as.data.frame(t(apply(df, 1, unlist)))

Convert nested list elements into data frame and bind the result into one data frame

Tag : r , By : Dave
Date : March 29 2020, 07:55 AM
will be helpful for those in need Borrowing from Spacedman and flodel here, we can define the following pair of recursive functions:
library(tidyverse)  # I use dplyr and purrr here, plus tidyr further down below

depth <- function(this) ifelse(is.list(this), 1L + max(sapply(this, depth)), 0L)

bind_at_any_depth <- function(l) {
  if (depth(l) == 2) {
  } else {
    l <- at_depth(l, depth(l) - 2, bind_rows)
# A tibble: 2 × 2
      a     b
  <dbl> <dbl>
1     1     2
2     3     4
bind_at_any_depth(x_ext) # From P Lapointe
# A tibble: 5 × 2
      a     b
  <dbl> <dbl>
1     1     2
2     5     6
3     7     8
4     1     2
5     3     4
bind_at_any_depth2 <- function(l) {
  if (depth(l) == 2) {
    l <- bind_rows(l, .id = 'source')
    l <- unite(l, 'source', contains('source'))
  } else {
    l <- at_depth(l, depth(l) - 2, bind_rows, .id = paste0('source', depth(l)))
# A tibble: 5 × 3
  source     a     b
*  <chr> <dbl> <dbl>
1  X_x_1     1     2
2  X_y_z     5     6
3 X_y_zz     7     8
4  Y_x_1     1     2
5  Y_y_1     3     4
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