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python re how to Extract fields use findall()?


python re how to Extract fields use findall()?

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python re how to Extract fields use findall()?
Tag : python , By : Joe Sweeney
Date : November 24 2020, 03:01 PM

Does that help After stripping all the unwanted escape characters, follwing regexs' can be applied to extract the required data:
import re

sample_text = """
staffs:
50 - 100

year_turnover:
0

url:
http://www.chinaanigu.com
"""

print re.findall(r"staffs:\n(.*)", sample_text) # catches anything followed by staffs:
>>> ['50 - 100']
print re.findall(r"year_turnover:\n(.*)", sample_text)
>>> ['0']

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Tags :

python re how to Extract fields use findall() , Extract integers in a string python re.findall , How to use findall or search to extract data in python , How to extract dates and all of the data following them using re.findall in python , re.findall python 3 ,

How to extract dates and all of the data following them using re.findall in python

Tag : python , By : francisco santos
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , I have a string, and I'm hoping to use regular expressions to separate some of the information from the string. , Try using the regex:
(\d{8}\s)10\.3\s-84\.8\$(.*?)(?=\d{8}|$)

How to use findall or search to extract data in python?

Tag : python , By : CSCI GOIN KILL ME
Date : March 29 2020, 07:55 AM
wish helps you You shouldn't call you string "str," because that's a built-in function. But here's an option for you:
# Find all of the entries
x = re.findall('(?<![AB]:)(?<=:).*?(?=[,}])', s)

['"mb"', '9', '"John"', '"/mb9/"', '0', '83498', '"mb"', '92', '"Mary"', 
'"/mb92/"', '0', '404', '"mb"', '97', '"Dan"', '"/mb97/"', '0', '139', 
'"mb"', '268', '"Jennifer"', '"/mb268/"', '0', '0', '"mb"', '289', '"Mike"', 
'"/mb289/"', '0', '0', '"mb"', '157', '"Sue"', '"/mb157/"', '0', '35200', 
'"mb"', '3', '"Rob"', '"/mb3/"', '0', '103047', '"mb"', '2', '"Tracy"', 
'"/mb2/"', '0', '87946', '"mb"', '26', '"Jenny"', '"/mb26/"', '0', '74870', 
'"mb"', '5', '"Florence"', '"/mb5/"', '0', '37261', '"mb"', '127', '"Peter"', 
'"/mb127/"', '0', '63711', '"mb"', '15', '"Grace"', '"/mb15/"', '0', '63243', 
'"mb"', '82', '"Tony"', '"/mb82/"', '0', '6471', '"mb"', '236', '"Lisa"', 
'"/mb236/"', '0', '4883']

# Break up into each section
y = []
for i in range(0, len(x), 6):
    y.append(x[i:i+6])

[['"mb"', '9', '"John"', '"/mb9/"', '0', '83498']
['"mb"', '92', '"Mary"', '"/mb92/"', '0', '404']
['"mb"', '97', '"Dan"', '"/mb97/"', '0', '139']
['"mb"', '268', '"Jennifer"', '"/mb268/"', '0', '0']
['"mb"', '289', '"Mike"', '"/mb289/"', '0', '0']
['"mb"', '157', '"Sue"', '"/mb157/"', '0', '35200']
['"mb"', '3', '"Rob"', '"/mb3/"', '0', '103047']
['"mb"', '2', '"Tracy"', '"/mb2/"', '0', '87946']
['"mb"', '26', '"Jenny"', '"/mb26/"', '0', '74870']
['"mb"', '5', '"Florence"', '"/mb5/"', '0', '37261']
['"mb"', '127', '"Peter"', '"/mb127/"', '0', '63711']
['"mb"', '15', '"Grace"', '"/mb15/"', '0', '63243']
['"mb"', '82', '"Tony"', '"/mb82/"', '0', '6471']
['"mb"', '236', '"Lisa"', '"/mb236/"', '0', '4883']]

# Name is 3rd value in each list and url is 4th
for i in y:
    name = i[2]
    url = i[3]

Failure to extract correct contents using re.findall() with python

Tag : python , By : terrestrial
Date : March 29 2020, 07:55 AM
Hope this helps The trouble is that the .+ is slurping up the first comma, you should change it to .+?, or better yet, [^,]+

Python 3.6 - Using re.findall to extract substring from Array-Element

Tag : python , By : Eniac
Date : March 29 2020, 07:55 AM
this will help I have had a longer break from Python and now I need your help again :)
import re
a = ['>lcl|NC_003078.1_gene_1 [gene=lacE] [locus_tag=SM_b21652] [location=1..1275]\n','>lcl|NC_003078.1_gene_2 [gene=lacF] [locus_tag=SM_b21653] [location=complement(22345..23337)]\n']
for i in a:
    val = re.findall("location\=.*?]", i)[0]     #Find Location.
    val = re.findall("\d+", val)                 #Find start and end.
    print("Start: {0} End:  {1}".format(val[0], val[1]))

Start: 1 End:  1275
Start: 22345 End:  23337

Extract integers in a string python re.findall

Tag : python , By : Pavel K.
Date : March 29 2020, 07:55 AM
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