List of lists, lamba and filtering results
Date : March 29 2020, 07:55 AM
This might help you I want to create two functions: 1) function which finds all elements less than zero in list (int list list) and then return these elements as list of (int list) type. , I think you are looking for something like this: let findnegative(d:int list list) =
d
|> List.map (fun x -> x |> List.filter (fun y -> y < 0))
|> List.collect id
let findeven (t:float list list) =
t
|> List.map (fun x -> x |> List.filter (fun y -> y % 2.0 = 0.0))
|> List.collect id
|> List.map int
let findnegative =
List.collect <| List.filter ((>)0)
let findeven =
List.collect <| List.filter (fun x -> x % 2. = 0.) >> List.map int
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Python List Comprehension: Affix strings from one list to the start of strings in another, for a list of lists
Tag : python , By : Nandor Devai
Date : March 29 2020, 07:55 AM
this will help I have two lists and I want to use a list comprehension to create a list of lists. The first list has some prefixes and the second has some suffixes. , You can also achieve this using list comprehension [[p+s for s in suffixes] for p in prefixes]
#[['t1_price', 't1_sales'], ['t0_price', 't0_sales']]
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python 3: how do I run a function over a list of lists of possible parameters and returning a dictionary of all results
Tag : python , By : Alecsandru Soare
Date : March 29 2020, 07:55 AM
may help you . Take a look at itertools.product to generate arguments, and then simply call the function: arguments = itertools.product(list_of_values_for_arg_1, list_of_values_for_arg_2, ..., list_of_values_for_arg_n)
# or
arguments = itertools.product(*list_of_lists)
for arg in arguments:
result=func(*arg)
{arg: func(*arg) for arg in itertools.product(*list_of_lists)}
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Beautiful Soup scrape of table is returning list of strings instead of list of lists
Date : March 29 2020, 07:55 AM
like below fixes the issue row is already a list, you don't need to put another list around it when you call f.writerow(). It should be f.writerow(list)
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Filtering through a list of lists of strings to get a list of lists of strings with a certain length
Date : March 29 2020, 07:55 AM
it helps some times In your case, I think that filter is more appropriate than takeWhile, just like Robin. Like this: λ>
λ> myFilter = filter (\[ls1, ls2] -> (7 > (length ls1 + length ls2)))
λ>
λ> myFilter [["aaa", "bbbb"],["c", "dd"]]
[["c","dd"]]
λ>
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