R: filtering by list(s) of strings and returning all results that start with the content of the lists

R: filtering by list(s) of strings and returning all results that start with the content of the lists

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R: filtering by list(s) of strings and returning all results that start with the content of the lists
Tag : r , By : lwl_seu
Date : November 24 2020, 03:01 PM

help you fix your problem I am not 100% sure what you want in output. I assume you want to filter rows that contains a pattern in AMI or STROKE without taking into account the "D".
The solution uses regex quantifier "?" to ignore D:
STROKE_regex <- sub(x = STROKE, pattern = "D", replacement = "D?")
AMI_regex <- sub(x = AMI, pattern = "D", replacement = "D?")

filter_at(DB, vars(contains("DIAGNOSECOL")),
        any_vars(grepl(x = ., pattern = paste(c(AMI_regex, STROKE_regex), collapse = "|"))))    

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List of lists, lamba and filtering results

Tag : development , By : user167963
Date : March 29 2020, 07:55 AM
This might help you I want to create two functions: 1) function which finds all elements less than zero in list (int list list) and then return these elements as list of (int list) type. , I think you are looking for something like this:
let findnegative(d:int list list) =
  |> List.map (fun x -> x |> List.filter (fun y -> y < 0))
  |> List.collect id

let findeven (t:float list list) = 
  |> List.map (fun x -> x |> List.filter (fun y -> y % 2.0 = 0.0))
  |> List.collect id
  |> List.map int
let findnegative =
  List.collect <| List.filter ((>)0)

let findeven = 
  List.collect <| List.filter (fun x -> x % 2. = 0.) >> List.map int

Python List Comprehension: Affix strings from one list to the start of strings in another, for a list of lists

Tag : python , By : Nandor Devai
Date : March 29 2020, 07:55 AM
this will help I have two lists and I want to use a list comprehension to create a list of lists. The first list has some prefixes and the second has some suffixes. , You can also achieve this using list comprehension
[[p+s for s in suffixes] for p in prefixes]
#[['t1_price', 't1_sales'], ['t0_price', 't0_sales']]

python 3: how do I run a function over a list of lists of possible parameters and returning a dictionary of all results

Tag : python , By : Alecsandru Soare
Date : March 29 2020, 07:55 AM
may help you . Take a look at itertools.product to generate arguments, and then simply call the function:
arguments = itertools.product(list_of_values_for_arg_1, list_of_values_for_arg_2, ..., list_of_values_for_arg_n)
# or
arguments = itertools.product(*list_of_lists)
for arg in arguments:
{arg: func(*arg) for arg in itertools.product(*list_of_lists)}

Beautiful Soup scrape of table is returning list of strings instead of list of lists

Tag : python , By : Saurabh
Date : March 29 2020, 07:55 AM
like below fixes the issue row is already a list, you don't need to put another list around it when you call f.writerow(). It should be

Filtering through a list of lists of strings to get a list of lists of strings with a certain length

Tag : haskell , By : DotNetWise
Date : March 29 2020, 07:55 AM
it helps some times In your case, I think that filter is more appropriate than takeWhile, just like Robin. Like this:
 λ> myFilter = filter (\[ls1, ls2] -> (7 > (length ls1 + length ls2)))
 λ> myFilter  [["aaa", "bbbb"],["c", "dd"]]
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