How to attach a simple data.frame to a SpatialPolygonDataFrame in R?
Date : March 29 2020, 07:55 AM
this one helps. Let df = data frame, sp = spatial polygon object and by = name or column number of common column. You can then merge the data frame into the sp object using the following line of code sp@data = data.frame(sp@data, df[match(sp@data[,by], df[,by]),])
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trying to attach a frame to a panel and draw a polygon , but there is no drawin on the frame
Tag : java , By : user186012
Date : March 29 2020, 07:55 AM
This might help you The basic problem is that you are overriding the wrong method in the JPanel. You have: @Override
public void paintComponents(Graphics g) {
@Override
public void paintComponent(Graphics g) {
^
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How to attach a title to a data frame in R?
Tag : r , By : user143038
Date : March 29 2020, 07:55 AM
will help you Though I'm not sure why you would want to do this, you could have both as elements of a list. As an example: report <- list()
report[[1]] <- "Report Name"
report[[2]] <- head(mtcars)
report
[[1]]
[1] "Report Name"
[[2]]
mpg cyl disp hp drat wt qsec vs am gear carb
Mazda RX4 21.0 6 160 110 3.90 2.620 16.46 0 1 4 4
Mazda RX4 Wag 21.0 6 160 110 3.90 2.875 17.02 0 1 4 4
Datsun 710 22.8 4 108 93 3.85 2.320 18.61 1 1 4 1
Hornet 4 Drive 21.4 6 258 110 3.08 3.215 19.44 1 0 3 1
Hornet Sportabout 18.7 8 360 175 3.15 3.440 17.02 0 0 3 2
Valiant 18.1 6 225 105 2.76 3.460 20.22 1 0 3 1
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Get row indices of data frame A according to multiple matching criteria in that data frame and another data frame, B
Date : March 29 2020, 07:55 AM
I hope this helps you . Let's say we have two data frames in R, df.A and df.B, defined thus: , 1) Using SQL it can readily be done in one statement: library(sqldf)
sqldf('select a.rowid
from "df.B" b
left join "df.A" a on obs_min >= bin_min and obs_max <= bin_max')
rowid
1 4
2 NA
3 5
4 2
5 NA
6 4
7 3
8 4
9 5
10 2
m <- merge(df.B, df.A)
stack(by(m, as.numeric(sub(".*_", "", m$obs_ID)),
with, c(which(obs_min >= bin_min & obs_max <= bin_max), NA)[1]))
values ind
1 4 1
2 NA 2
3 5 3
4 2 4
5 NA 5
6 4 6
7 3 7
8 4 8
9 5 9
10 2 10
sapply(1:nrow(df.B), function(i)
c(which(df.A$bin_max >= df.B$obs_max[i] & df.A$bin_min <= df.B$obs_min[i]), NA)[1])
[1] 4 NA 5 2 NA 4 3 4 5 2
mapply(function(x, y) c(which(x >= df.A$bin_min & y <= df.A$bin_max), NA)[1],
df.B$obs_min,
df.B$obs_max)
seq_len(nrow(df.A)) %*%
(outer(df.A$bin_max, df.B$obs_max, ">=") & outer(df.A$bin_min, df.B$obs_min, "<="))
[,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10]
[1,] 4 0 5 2 0 4 3 4 5 2
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R:How to attach parts of a data frame with different headers and/or an overflowing piece of the dat frame, Cont
Date : March 29 2020, 07:55 AM
hop of those help? Okie. Figured this out. All I had to do was to change the grep to ignore case. nm1 <- c("EA_A", "EA_B", "EA_C", "EA_D", "EA_E", "EA_F", "EA_G","EA_H")
temp = split(df1, cumsum(grepl("[A-Z]", df1$tar, ignore.case = TRUE))) %>%
map(~ if(any(grepl("[A-Z]", .$tar, ignore.case = TRUE))) {
names(.) <- unlist(.[1,])
.[-1,]
} else .) %>%
map(~ .[names(.) != ""]) %>%
bind_rows %>%
group_by(Keg) %>%
summarise_at(vars(intersect(nm1, names(.))), funs(sum(as.numeric(.),
na.rm = TRUE)))
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