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Checking if a user's entry is an integer using try catch statements


Checking if a user's entry is an integer using try catch statements

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Checking if a user's entry is an integer using try catch statements
Tag : java , By : Bruce
Date : November 24 2020, 03:01 PM

should help you out I assume your code isn't working?
The way I'd do it is to create a Boolean method and return true or false
boolean checkIfNumber(String s) {
    try {
        Integer.parseInt(s);
    } catch (NumberFormatException ex) {
        JOptionPane.showMessageDialog(null, "Enter a number!");
        return false;
    }
    return true;
}
if (checkIfNumber(txtWeight.getText())) {
     //do your code here
} else {
     //do something else if necessary if the return is false
}

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Questions regarding ordering of catch statements in catch block - compiler specific or language standard?


Tag : chash , By : Nickolas
Date : March 29 2020, 07:55 AM
will be helpful for those in need According to the standard, the order is significant. Basically the first catch that matches the exception will be caught.
a) Because catch(...) will make any following catches irrelevant, the standard only allows it to be the last catch.

Replace multiple if statements when checking for multiple integer ranges


Tag : javascript , By : phil
Date : March 29 2020, 07:55 AM
wish help you to fix your issue First, it's not very good to use object for a variable name in javascript. I'm using 'o' instead. As i can figure out from your code, the values in code blocks can be derived from conditional statements:
var scoreLimits = [0,40,65,85,95,100];

for(var i = 1; i < scoreLimits.length; i++)
{
    var limit = scoreLimits[i];
    if ( userScore <= limit )
    {
        o.setMinValue(scoreLimits[i-1]);
        o.setMaxValue(limit);
        break;
    }
}
var mapper = {};
for(var i = 0; i < scoreLimits.length - 1; i++)
{
    var limits = { minValue : scoreLimits[i], maxValue : scoreLimits[i+1] };
    for (var j = scoreLimits[i] + 1; j <= scoreLimits[i + 1]; j++)
    {
        mapper[j] = limits;
    }
}

checking if an input of an integer is a string with try catch


Tag : java , By : user170635
Date : March 29 2020, 07:55 AM
may help you . I want the try-catch to loop until i input a proper integer, but all i am having is an infinite loop when i enter a string : , Replace the loop with following:
while (c == 1) {
            try {
                System.out.println("enter a number");
                num = Integer.parseInt(scan.nextLine());
                c=2;
            } catch (Exception e) {
                System.out.println("enter a Number please : ");
            }
        }

If statements vs. Try/Catch for checking against array bounds


Tag : chash , By : Arun Thomas
Date : March 29 2020, 07:55 AM
this will help Interestingly enough, your question is not language independent on the one hand.
In languages such as C, Java, C++, C# ... people prefer the "LBYL" (Look Before You Leap) pattern; whereas languages such as python heavily emphasize "EAFP" (it's Easier to Ask Forgiveness than Permission).

try-catch block in Java - execution statements in catch code


Tag : java , By : chudq7
Date : March 29 2020, 07:55 AM
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