mysqli_stmt::bind_param Number of variables doesn't match number of parameters in prepared statement
Date : March 29 2020, 07:55 AM
Hope that helps This is clear example showing why mysqli is totally unusable with prepared statements. Either use PDO or manually parsed custom placeholders, like safemysql does.
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Warning: mysqli_stmt::bind_param() Number of variables doesn't match number of parameters in prepared statement
Tag : php , By : user178709
Date : March 29 2020, 07:55 AM
Hope this helps Your query preparation contains zero parameters, since you just dumped the values in there, completely defeating the purpose of prepared statements. Instead, try this: if (!($stmt = $mysqli->prepare("INSERT INTO table(id, name, votes) VALUES (?,?,?)"))) {
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mysqli_stmt::bind_param(): Number of variables doesn't match number of parameters in prepared statement
Tag : php , By : agjimenez
Date : March 29 2020, 07:55 AM
hop of those help? Modification is: $stmt->bind_param ( "ss", $user, $pass); because 1 data type is not defind in bind_param (). bind_param() will take two arguments 1st one is types (i, d, s, b) corresponding datatype in your query(?) and 2nd arg are values. public function login($_username, $_password) {
$this->sessionOpen ();
if (empty($_username)) {
$this->log->error ( "Username vuoto" );
throw new AuthLoginFailed ();
}
if (empty($_password)) {
$this->log->error ( "Password vuota" );
throw new AuthLoginFailed ();
}
$db = new mysqli ( $this->sql ['server'], $this->sql ['username'], $this->sql ['password'], $this->sql ['database'] );
if (mysqli_connect_errno ()) {
$this->log->error ( "Errore di connessione a mysql: " . mysqli_error ( $db ) );
throw new MysqliConnectionError ( "Mysqli error: " . mysqli_error ( $db ) );
}
$stmt = $db->prepare ( "SELECT id,org_id,org_group_id,people_id FROM users WHERE 'username' = ? AND 'password' = ?" );
if (! $stmt) {
$this->log->error ( "Mysqli prepare error: " . mysqli_error ( $db ) );
throw new MysqliPrepareException ( "Mysqli error: " . mysqli_error ( $db ) );
}
echo md5 ( $_username ) . "---" . md5 ( $_password );
//on page username and password is showed at this point
$user=md5 ( $_username );
$pass=md5 ( $_password );
$stmt->bind_param ( "ss", $user,$pass);
/* Execute it */
$stmt->execute ();
if (! $stmt) {
$this->log->error ( "Mysqli prepare error: " . mysqli_error ( $db ) );
throw new MysqliExecuteException ( "Mysqli error: " . mysqli_error ( $db ) );
}
$stmt->fetch($rst);
echo "results: " . $rst->num_rows; //output of this: results:
if ($rst->num_rows == 0) {
throw new AuthLoginFailed ();
}
/* Close statement */
$stmt->close ();
/* Close connection */
$db->close ();
}
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Mysqli:mysqli_stmt::bind_param(): Number of variables doesn't match number of parameters in prepared statement
Tag : php , By : silvervino
Date : March 29 2020, 07:55 AM
Hope this helps It is failing because mysqli is not PDO and you cannot bind in a loop. Thus you have to use tricks to bind an array in mysqli. Luckily, if your PHP version is 5.6 or 7, you can use this code: $stmt = $db->prepare($query);
$types = str_repeat('s', count($param));
$statement->bind_param($types, ...$param);
$statement->execute();
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mysqli_stmt::bind_param(): Number of variables doesn't match number of parameters in prepared statement on line 64
Tag : php , By : Enrique Anaya
Date : March 29 2020, 07:55 AM
I wish this helpful for you That's not how bind_param works in mysqli. Maybe you were thinking of PDO? In mysqli you have to bind them all at once with one statement. $stmtPruefung->bind_param("sss",$username, $key, $hwid);
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