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display null value using rank functions in oracle sql


display null value using rank functions in oracle sql

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display null value using rank functions in oracle sql
Tag : sql , By : Rohii
Date : November 18 2020, 03:01 PM

I hope this helps . This is an extension of another question: How to display null value when the record is present more than one time in oracle sql , If I understand correctly:
select (case when row_number() over (partition by cid order by c_name) = 1 then cid end) as cid,
       c_name,
       (case when max(c_tax) is not null then 'yes' else 'no' end) as c_tax
from t
group by c_id, c_name
order by c_id, c_name;

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Oracle can I use scalar functions in WHERE Clause? or a NULL issue


Tag : oracle , By : Jouni
Date : March 29 2020, 07:55 AM
should help you out Oracle is peculiar in that the empty string ('') and NULL are the same thing. It is as if you are saying:
trim(t1.c1) != NULL
trim(t1.c1) IS NOT NULL

Setting rank to NULL using RANK() OVER in SQL


Tag : sql , By : brij
Date : March 29 2020, 07:55 AM
I wish this help you In a SQL Server DB, I have a table of values that I am interested in ranking. , You can try a CASE statement:
SELECT
    CASE WHEN Value IS NULL THEN NULL
         ELSE RANK() OVER (ORDER BY VALUE DESC)
    END AS RANK,
    USER_ID,
    VALUE
FROM yourtable

What's the difference between RANK() and DENSE_RANK() functions in oracle?


Tag : sql , By : TheDave1022
Date : March 29 2020, 07:55 AM
I wish did fix the issue. RANK gives you the ranking within your ordered partition. Ties are assigned the same rank, with the next ranking(s) skipped. So, if you have 3 items at rank 2, the next rank listed would be ranked 5.
DENSE_RANK again gives you the ranking within your ordered partition, but the ranks are consecutive. No ranks are skipped if there are ranks with multiple items.
with q as (
select 10 deptno, 'rrr' empname, 10000.00 sal from dual union all
select 11, 'nnn', 20000.00 from dual union all
select 11, 'mmm', 5000.00 from dual union all
select 12, 'kkk', 30000 from dual union all
select 10, 'fff', 40000 from dual union all
select 10, 'ddd', 40000 from dual union all
select 10, 'bbb', 50000 from dual union all
select 10, 'xxx', null from dual union all
select 10, 'ccc', 50000 from dual)
select empname, deptno, sal
     , rank() over (partition by deptno order by sal nulls first) r
     , dense_rank() over (partition by deptno order by sal nulls first) dr1
     , dense_rank() over (partition by deptno order by sal nulls last) dr2
 from q; 

EMP     DEPTNO        SAL          R        DR1        DR2
--- ---------- ---------- ---------- ---------- ----------
xxx         10                     1          1          4
rrr         10      10000          2          2          1
fff         10      40000          3          3          2
ddd         10      40000          3          3          2
ccc         10      50000          5          4          3
bbb         10      50000          5          4          3
mmm         11       5000          1          1          1
nnn         11      20000          2          2          2
kkk         12      30000          1          1          1

9 rows selected.

how to assign a rank for null values with previous first non-null value in oracle


Tag : sql , By : Enrique Anaya
Date : March 29 2020, 07:55 AM
Any of those help I need to assign a rank to some null values over ordered rows. , If you know that the values are increasing, you can just use max():
select id, inx, max(num) over (partition by id order by inx) as num
select id, inx,
       (case when num is null
             then lag(num) over (partition by id order by inx)
             else num
        end)as null;
select id, inx,
       (case when num is null
             then lag(num ignore nulls) over (partition by id order by inx)
             else num
        end)as null

how to assign a rank for non null values in oracle


Tag : sql , By : Simon Hogg
Date : March 29 2020, 07:55 AM
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