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Call sent to two reciever with different userId


Call sent to two reciever with different userId

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Call sent to two reciever with different userId
Tag : ios , By : user184415
Date : December 05 2020, 12:22 PM

This might help you We are using the sinch SDK (ios and android). We are using the phone number as identifier. We are using the sandbox host. A, B and C have differents userId. We found an issue when A call B, this call is recieved by B and C. for advance , Finally i found the solution. WHen logging out you should call the
        SinchManager.sharedInstance.sinchClient?.stopListeningOnActiveConnection()
        SinchManager.sharedInstance.sinchClient?.terminateGracefully()

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Give a Call to BroadCast Reciever Through An Activity


Tag : android , By : mgaspar
Date : March 29 2020, 07:55 AM
I wish this helpful for you Remove the space from the action name. Use the name when you create the Intent.

How call an Intent switch from a c2dm message reciever


Tag : android , By : user185144
Date : March 29 2020, 07:55 AM
wish helps you I have a simple c2dm message receiver class which is called whenever the device receives a c2dm message. In one case, I want to have the message receiver class perform an intent switch to load a different activity. Android throws an exception when this happens , Add this to your intent
 Intent.FLAG_ACTIVITY_NEW_TASK

android - how to call a method from another activity, from a reciever class?


Tag : android , By : Gabe
Date : March 29 2020, 07:55 AM
I wish this help you Then you should either
1) put your onReceive method in your pol_viewactivity; or,
public interface ExampleListener {
    onMsgReceive(String msg);
}
private ExampleListener listener;

public void setExampleListener(ExampleListener listener) {
    this.listener = listener;
}
if (listener != null) {
    listener.onMsgReceive("Your message to pass");
}

BroadcastReceiver doesn't work with <reciever ... ></reciever>


Tag : android , By : eusden
Date : March 29 2020, 07:55 AM

why userid not change the global userid , it never used userid function declare inside foo


Tag : javascript , By : Arun Thomas
Date : January 02 2021, 06:48 AM
wish helps you In JavaScript, declarations are hoisted to the top of their enclosing scope, so when you declare the function id, it is processed as this:
function foo() {
    function userid() {} // Even though you placed this last, it's processed first!
    userid = 'test2';
    return;
}
foo();
console.log(userid);
var userid = "something";

function foo() {
  // Hoisting is why we can call functions before we've declared them!
  userid();
  window.userid = 'test2'; // Access the global through the global object
  return;
  // Normally, nothing after a return is processed, but because of 
  // hoisting, this function declaration will be processed first.
  function userid() {
    console.log("hello from userid");
  } 
}
foo();
console.log(userid);
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