Define print format for custom datatype

Define print format for custom datatype

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Define print format for custom datatype
Tag : haskell , By : Vlad Sirenko
Date : December 05 2020, 12:22 PM

With these it helps For the exercise that I'm doing, I implemented a datatype that is similar to Maybe: , You can just use deriving (Show) on your data type:
data Optional a = Some a | None deriving (Show)

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How do I define custom datatype in xsd?

Tag : xml , By : k19k
Date : March 29 2020, 07:55 AM
Does that help I want to check if a field in my XML is of type positive double/decimal. There is a type="xs:positiveInteger" datatype in XSD but no positive double or decimal. Is there a way to achieve this either by defining custom datatype or some other way?
<xs:element name="data">
    <xs:restriction base="xs:float">
      <xs:minInclusive value="0"/>

Define Regular Expression Validation for custom DataType in MVC4

Tag : regex , By : Nulq
Date : March 29 2020, 07:55 AM
around this issue I found out that in order to get MVC4 to render the correct data attributes to the input field, I'd need to replace the hyphens with underscores in the anonymous object passed to the TextBox helper. Here's the code that I ended up with:
    var ssn = (string)ViewData.TemplateInfo.FormattedModelValue;
    if (!String.IsNullOrWhiteSpace(ssn) && ssn.Length == 11)
        ssn = "###-##-" + Model.Substring(Model.Length - 4, 4);
    else {
        ssn = "";
@Html.TextBox("", ssn,
        @class = "text-box single-line ssn",
        data_val = "true",
        data_val_regex_pattern = @"^(\d{3}|###)-(\d{2}|##)-\d{4}$",
        data_val_regex = "Expected pattern is ###-##-####",
        placeholder = "###-##-####"

Custom Define user datatype vb.net - lika double

Tag : .net , By : Brownell
Date : March 29 2020, 07:55 AM
wish of those help If you are willing to use something other than the / symbol, the easiest approach is to define an Extension Method on Double:
Module DoubleExtensions

    Public Function Div(value1 As Double, value2 As Double) As Double
        Return Math.Round(value1 / value2, 3)
    End Function

End Module
Private Sub Test()
    Dim x As Double = 1
    Dim y As Double = 3

    Dim z As Double = x.Div(y)

End Sub
Public Class MyDouble
    Private m_Double As Double
    Public Sub New(value As Double)
        m_Double = value
    End Sub

    Public Shared Operator =(value1 As MyDouble, value2 As Double) As Double
        value1.Value = value2
        Return value2
    End Operator
    Public Shared Operator <>(value1 As MyDouble, value2 As Double) As Double
        Return value2
    End Operator
    Public Shared Operator /(value1 As MyDouble, value2 As MyDouble) As Double
        Return Math.Round(value1.Value / value2.value, 3)
    End Operator

    Public Property Value As Double
            Return m_Double
        End Get
        Set(value As Double)
            m_Double = value
        End Set
    End Property
End Class
    Dim x As New MyDouble(1)
    Dim y As New MyDouble(3)

    Dim z As Double = x / y

A better #define print std::cout<<boost::format

Tag : cpp , By : Lucas Thompson
Date : March 29 2020, 07:55 AM
will be helpful for those in need To quickly insert brief debug statements I would like to turn , I would suggest something like
#define print(x) std::cout << (x) << std::endl
print(boost::format("%s") % str);
#include <iostream>
#include <boost/format.hpp>

class Forwarder
  Forwarder(const std::string& s)
    : f(s)

  template <typename T>
  Forwarder& operator%(const T& t)
    f % t;
    return *this;
    // You could even return a reference to f here instead if you wanted

    std::cout << f << std::endl;

  boost::format f;

#define print(x, y) { Forwarder f(x); f % y; }

int main()
  std::string str("Hallo");
  int i = 123, j = 456;
  print("%s %d %d", str % i % j);
struct END {};
template <>
Forwarder& Forwarder::operator%<END>(const END& t)
  std::cout << f << std::endl;
  return *this;
print("%s %d %d") % str % i % j % END;
void operator<<=(Logger& l, const Forwarder& f) { ... }
DebugLogger <<= Forwarder("%s %d %d") % str % i % j;
void operator,(const Forwarder& f, Logger& l) { ... }
Forwarder("%s %d %d") % str % i % j, DebugLogger;

Use macro to define print format arguments

Tag : cpp , By : micate
Date : March 29 2020, 07:55 AM
this one helps. I want to define the format %lld and use intro printf or snprintf , You can use string literal concatenation. Since
#define CUSTOM_FORMAT "%lld"
printf("It works " CUSTOM_FORMAT, var); // <-- no comma ;)
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