How to parse JsonArray values in Android

How to parse JsonArray values in Android

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How to parse JsonArray values in Android
Tag : android , By : eataix
Date : November 28 2020, 11:01 PM

I think the issue was by ths following , Yours (as I can see from the link you've posted) is a single JSON message {...} wich contains many nodes ("A","B", "E", "F"... and so on). Every node is a JSON Array wich contains some JSON Objects.
You must Get first the JSON Objects: "A", "B",... this way:
String result = EntityUtils.toString(response.getEntity()); //the result of HTTP call
JSONObject JO = new JSONObject(result);
JSONArray ja = JO.getJSONArray("A");
JSONArray jb = JO.getJSONArray("B");
for(int i=0; i< ja.length(); i++){
    JSONObject jo = ja.getJSONObject(i);
    String id = jo.getString("id");
    String name = jo.getString("name");

    System.out.println("id: " + id + "");
    System.out.println("name: " + name + "");

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How to parse jsonArray in android

Tag : android , By : harley.holt
Date : March 29 2020, 07:55 AM
I wish this helpful for you i am new to json parsing...please help me parsing the following code in android , Get your response using the below method:
public static String getWebserviceResponse(String p_url) {
    String m_response = null;
    HttpClient client = new DefaultHttpClient();
    HttpGet httpget = new HttpGet(p_url);
    HttpResponse response;
    System.err.println("Request URL---------->"+ p_url);
    try {
        response = client.execute(httpget);
        if (response.getStatusLine().getStatusCode() == HttpStatus.SC_OK) {
            InputStream in = response.getEntity().getContent();
            StringBuilder sb = new StringBuilder();
            String line = "";
            BufferedReader bf = new BufferedReader(
                    new InputStreamReader(in));
            while ((line = bf.readLine()) != null) {
            m_response = sb.toString();

    } catch (ClientProtocolException e1) {
        // TODO Auto-generated catch block
    } catch (IOException e1) {
        // TODO Auto-generated catch block
    return m_response;
 String response=getWebserviceResponse("your request Url");
    JSONObject jo = new JSONObject(response);

              JSONArray resultarr = jo.getJSONArray("msg");
        for (int i = 0; i < resultarr.length(); i++) 

                      JSONObject jObjresult = resultarr.getJSONObject(i);
                         String index = jObjresult .getString("index");
                         String userId=jObjresult .getString("uid"));
                     JSONArray jObj = jObjresult.getJSONArray("msg");
                        for (int j = 0; j < jObj.length(); j++) 
                  //Get the messages only from the Sender C.
                           String sender=jObj.getString("sender");
                                  String message = jObj.getString("message");

Parse JsonArray without key in android

Tag : android , By : Frank Rotolo
Date : March 29 2020, 07:55 AM
To fix this issue i have a json response but is this standard format? ,
i have a json response but is this standard format?
new JSONObject(result.toString().substring(1, result.length() - 2));
new JSONArray(result.toString().substring(1, result.length() - 2));
new JSONArray(result.toString());

Android: Parse 2 jsonArray

Tag : android , By : Adam May
Date : March 29 2020, 07:55 AM
like below fixes the issue How i can parse 2 json Array in Android? Plz see the following code;
JSONObject object  = new JSONObject(your-string);

    JSONArray details=object.getJSONArray("details");
for(int j=0;j<details.length();j++){
       JSONObject detail= details.getJSONObject(i);
    String price = detail.getString("price");
    JSONArray colors = object.getJSONArray("colors");

    for(int i=0;i<colors.length();i++){
       JSONObject obj= colors.getJSONObject(i);
       // parse your json here
    String color = obj.getString("color")


how to parse jsonArray in android?

Tag : android , By : wrb302
Date : March 29 2020, 07:55 AM
it helps some times Your error org.json.JSONException: Value of type org.json.JSONArray cannot be converted to JSONObject clearly says that you are trying to parse a JSONArray to a JSONObject
Do this
JSONArray reader = new JSONArray(json);
JSONObject jsonArray = reader.getJSONObject(0).optJSONObject("scores"); // replace 0 with your own index

Android : parse a JSONArray

Tag : android , By : Ashley
Date : March 29 2020, 07:55 AM
it fixes the issue I would need help to parse this JSONArray in my Android app. I'm a bit confused with JSONObjects and JSONArrays : , Here is your code to parse data,
private void parseData(){
        try {
            JSONArray jsonArray=new JSONArray(response);
            JSONObject jsonObject=jsonArray.getJSONObject(0);
            JSONArray jsonArrayNid=jsonObject.getJSONArray("nid");
            JSONArray jsonArrayUid=jsonObject.getJSONArray("uid");
            JSONArray jsonArrayField_image=jsonObject.getJSONArray("field_image");
            for(int i=0;i<jsonArrayNid.length();i++){
                JSONObject jsonObjectNid=jsonArrayNid.getJSONObject(i);
                String value=jsonObjectNid.getString("value"); //here you get your nid value
            for(int i=0;i<jsonArrayUid.length();i++){
                JSONObject jsonObjectUid=jsonArrayUid.getJSONObject(i);
                String target_id=jsonObjectUid.getString("target_id"); //here you get your uid target_id value
                String url=jsonObjectUid.getString("url"); //here you get your uid url value
            for(int i=0;i<jsonArrayField_image.length();i++){
                JSONObject jsonObjectFieldImage=jsonArrayField_image.getJSONObject(i);
                String target_id=jsonObjectFieldImage.getString("target_id");
                String alt=jsonObjectFieldImage.getString("alt");
                String title=jsonObjectFieldImage.getString("title");
                String width=jsonObjectFieldImage.getString("width");
                String height=jsonObjectFieldImage.getString("height");
                String url=jsonObjectFieldImage.getString("url");
        } catch (JSONException e) {

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