How to fetch specific elements from an array and create a new array based on the comparison of an array key's value?
Date : March 29 2020, 07:55 AM
I wish did fix the issue. Use array_filter: $filtered = array_filter($yourArray, function($element) use($test_pack_id) {
return $element['test_pack_id'] == $test_pack_id;
});
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nested array object comparison with another array of elements and create new array using Javascript or ES6
Date : March 29 2020, 07:55 AM
it helps some times You can basically filter the sections from sectionDetail based on whether the object.id inside it is included in the sections of abc. I have mapped the indexes to number in both cases since one was string and the other was integer. sectionDetail = [{id: 1, name:'ma'}, {id: 2, name:'na'}, {id: 3, name:'ra'}, {id: 4, name:'ka'}, {id: 5, name:'pa'}];
abc = [{id:'1', name:'zam', sections:['1',4]}, {id:'2', name:'dam', sections:['3']}, {id:'3', name:'nam', sections:['2','4']}];
xyz = abc.map(item => ({...item, sections: sectionDetail.filter(sect => item.sections.map(id => parseInt(id)).includes(parseInt(sect.id)))}));
console.log(xyz);
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Sorting an array based on comparison with another array of same elements in different order
Date : March 29 2020, 07:55 AM
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Show first 4 elements from one array and first 1 element from another array, untill array elements exists
Date : March 29 2020, 07:55 AM
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How do I element-wise multiply an array of 6 elements with an array of 12 elements with the smaller array repeating?
Date : January 02 2021, 06:48 AM
fixed the issue. Will look into that further I have an array [x1, x2, x3, x4, x5, x6] and another array [y1, y2, y3,...y12]. , np.resize x = np.array([1, 2, 3])
y = np.array([1, 2, 3, 4, 5, 6])
np.resize(x, y.size) * y
array([ 1, 4, 9, 4, 10, 18])
x = np.array([1, 2, 3])
y = np.array([1, 2, 3, 4, 5, 6, 7, 8])
np.resize(x, y.size) * y
array([ 1, 4, 9, 4, 10, 18, 7, 16])
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