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Comparison of one element in array to all other elements in same array


Comparison of one element in array to all other elements in same array

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Comparison of one element in array to all other elements in same array
Tag : c , By : Mariocki
Date : November 28 2020, 11:01 PM

This might help you Instead of incrementing no_of_unique within the scope of the inner loop, you may simply break after finding an element that is equal to split[f]. Then, outside the inner loop, you should check whether p is equal to length2, which would mean that the inner loop did not break and traversed all the elements till the end of the array. (i.e. did not encounter an element equal to split[f])
for (f = 0; f < length2; f++) {
    if (split[f] != 0) {
        for (p = 0; p < length2 ; p++) {
            if( f != p && (split[p] != 0) && (compareThem(split[f],split[p]) == 1)) {
                break;
            }
        }
        if (p == length2) {
            no_of_unique++;
        }
    }
}

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How to fetch specific elements from an array and create a new array based on the comparison of an array key's value?


Tag : php , By : Erwin
Date : March 29 2020, 07:55 AM
I wish did fix the issue. Use array_filter:
$filtered = array_filter($yourArray, function($element) use($test_pack_id) {
  return $element['test_pack_id'] == $test_pack_id;
});

nested array object comparison with another array of elements and create new array using Javascript or ES6


Tag : javascript , By : Chris Lomax
Date : March 29 2020, 07:55 AM
it helps some times You can basically filter the sections from sectionDetail based on whether the object.id inside it is included in the sections of abc. I have mapped the indexes to number in both cases since one was string and the other was integer.
sectionDetail = [{id: 1, name:'ma'}, {id: 2, name:'na'}, {id: 3, name:'ra'}, {id: 4, name:'ka'}, {id: 5, name:'pa'}];

abc = [{id:'1', name:'zam', sections:['1',4]}, {id:'2', name:'dam', sections:['3']}, {id:'3', name:'nam', sections:['2','4']}];

xyz = abc.map(item => ({...item, sections: sectionDetail.filter(sect => item.sections.map(id => parseInt(id)).includes(parseInt(sect.id)))}));

console.log(xyz);

Sorting an array based on comparison with another array of same elements in different order


Tag : algorithm , By : Robert Daniel Pickar
Date : March 29 2020, 07:55 AM

Show first 4 elements from one array and first 1 element from another array, untill array elements exists


Tag : php , By : Bharath
Date : March 29 2020, 07:55 AM

How do I element-wise multiply an array of 6 elements with an array of 12 elements with the smaller array repeating?


Tag : python , By : kakashi_
Date : January 02 2021, 06:48 AM
fixed the issue. Will look into that further I have an array [x1, x2, x3, x4, x5, x6] and another array [y1, y2, y3,...y12]. , np.resize
x = np.array([1, 2, 3])
y = np.array([1, 2, 3, 4, 5, 6])

np.resize(x, y.size) * y

array([ 1,  4,  9,  4, 10, 18])
x = np.array([1, 2, 3])
y = np.array([1, 2, 3, 4, 5, 6, 7, 8])

np.resize(x, y.size) * y

array([ 1,  4,  9,  4, 10, 18,  7, 16])
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