Why doesn't strlen() return the correct number of bytes here?

Why doesn't strlen() return the correct number of bytes here?

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Why doesn't strlen() return the correct number of bytes here?
Tag : objective-c , By : Michael Gunderson
Date : November 28 2020, 11:01 PM

around this issue , use below code to get data byte length:
NSString* data = @"UdmAjkmNQs79+J/a/MVVSACRkIo=";
NSData *key = [[NSData alloc] initWithBase64EncodedString:data options:NSDataBase64DecodingIgnoreUnknownCharacters];
NSLog(@"Length:  %lu", [key length]);

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mb_strlen() & strlen() don't return correct values from an Ajax call to PHP

Tag : php , By : quasarkitten
Date : March 29 2020, 07:55 AM
I wish this helpful for you PHP is a byte processor, it is not charset-aware. That has a number of tricky consequences.
Strlen() returns the length in bytes, not the length in characters. This is because php's "string" type is actually an array of bytes. Utf8 uses more than one byte per character for the 'special characters'. Therefore strlen() will only give you the right answer for a narrow subset of text (= plain english text).

char array in structs - why does strlen() return the correct value here?

Tag : c , By : Steve O.
Date : March 29 2020, 07:55 AM
I wish did fix the issue. TL;DR Answer: No, this is well-defined behaviour.
Explanation: As per the C11 standard document, chapter 6.7.9, initalization,
 char name[10];
{ 31, {'J', 'a', 'n'} },

strlen doesn't return the correct value with pointer to an array

Tag : c , By : Roel van Dijk
Date : March 29 2020, 07:55 AM
should help you out I have the following code: , In this code:
char* realtor_command[120];
for(int i=0;i<REALTOR_MAX_COMMAND_LENGTH;i++){
char* realtor_command[120];
for (int i = 0; i < 120; i++) {
    realtor_command[i] = NULL;

char input_buffer[REALTOR_MAX_COMMAND];

// Read in one string, then copy it so we can re-use the buffer
fgets(input_buffer, REALTOR_MAX_COMMAND, stdin);
realtor_command[0] = strdup(input_buffer);
if (strstr(input_buffer, "\n") == NULL) {
    // error, input didn't fit in our buffer!

Function strlen() not return correct length

Tag : php , By : Bado
Date : March 29 2020, 07:55 AM
I wish this help you I dont know why strlen() doesnt return correct length of string. Actual length is 29 , but strlen() return 41 . Please help. , Your string with the HTML entities escaped is:
&lt;td bgcolor=#FFFFFF&gt;2-0&lt;/td&gt;
echo strlen('<td bgcolor=#FFFFFF>2-0</td>'); // 28
echo strlen(htmlentities('<td bgcolor=#FFFFFF>2-0</td>')); // 40

strlen not returning correct number of characters

Tag : c , By : davidg
Date : March 29 2020, 07:55 AM
this will help strlen() is for determining the length of a string. In C, A string has a null character at the end,else it is not a string. Unless the data read includes a null character, it is not a string.
Instead, use the return value from read() to determine the length read. To print a ssize_t, cast to a wide type, such as long long or intmax_t (better), as ssize_t lacks a specified print specifier.1 2
char buffer[BUF_SIZE];   // BUF_SIZE = 100
// ssize_t readIn = read(STDIN_FILENO, &buffer, BUF_SIZE);
ssize_t readIn = read(STDIN_FILENO, buffer, BUF_SIZE);

// printf("strlen=%lu\n", strlen(buffer));
printf("length = %lld\n", (long long) readIn);
// or
printf("length = %jd\n", (intmax_t) readIn);
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