Average and group by in SQL but for best 10 records only

Average and group by in SQL but for best 10 records only

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Average and group by in SQL but for best 10 records only
Tag : sql , By : Lars
Date : November 28 2020, 11:01 PM

wish of those help Given: A ranking table (id, user_id, score, group_id, date) , you can do this:
            ROUND(AVG(r.score)::NUMERIC, 2) AS score,
            SUM(score) AS score_sum,
            MAX(r.date) AS ranking_timestamp,
            a.name AS group_name,
            a.id AS group_id
        ranking r, group a
        WHERE a.id = r.group_id
        GROUP BY a.id,a.name
        ORDER BY AVG(r.score) DESC,MAX(r.date) ASC


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Average of latest N records per group

Tag : mysql , By : lhoBas
Date : March 29 2020, 07:55 AM
To fix this issue My current application calculates a point average based on all records for each user: , Try this:
SELECT user_id, AVG(points) AS pts 
FROM (SELECT user_id, IF(@uid = (@uid := user_id), @auto:=@auto + 1, @auto := 1) autoNo, points
      FROM players, (SELECT @uid := 0, @auto:= 1) A 
      WHERE points != 0 
      ORDER BY user_id, match_id DESC
     ) AS A 
WHERE autoNo <= 30
GROUP BY user_id;

Query to find the average of the number of records per group

Tag : mysql , By : James Lupiani
Date : March 29 2020, 07:55 AM
I wish did fix the issue. I have a Table having 2 Columns i.e FarmerName,PesticideUsed and Town. , Average number of farmers using a pesticide:
SELECT PesticideUsed ,AVG(num)
SElECT PesticideUsed ,COUNT(*) as num
FROM yourTable
GROUP BY PesticideUsed) a
GROUP BY PesticideUsed 
SELECT town ,AVG(num)
SElECT town ,COUNT(*) as num
FROM yourTable
GROUP BY town) a
GROUP BY  town 

T-SQL - Create a trigger to update the updated record's average time with the average of similar records over the past 9

Tag : sql , By : Boyer C.
Date : March 29 2020, 07:55 AM
I hope this helps . Try this. Notice how the UPDATE joins to the inserted table so that it will handle multiple inserts, instead of using variables.
ON dbo.BatchLog

SET RollingAvgTime = (
 SELECT AVG(DATEDIFF(minute,0,ElapsedTime))
 FROM BatchLog b2
 WHERE b2.BatchLogNId = b.BatchLogNId
 AND b2.EndTime <= DATEADD(MONTH, -3, GETDATE())
FROM BatchLog b
INNER JOIN inserted I
  ON b.BatchLogNId=i.BatchLogNId


return average of counts of records after a group by statement

Tag : python , By : Jeskl
Date : November 02 2020, 09:01 AM
I wish this helpful for you Here is the answer.
In your case, using the table definition provided:
from sqlalchemy import cast, func
from sqlalchemy.types import TIME, DATE
from sqlalchemy.sql import between

time_from = ...  # get filter time maybe using datetime.time()
time_to = ...  # idem
counts = session.query(func.count('*').label('count')).\
    filter(between(cast(MyClass.created, TIME),
    group_by(cast(MyClass.created, DATE))

avg = session.query(func.avg(counts.subquery().columns.count)).scalar()

print avg

Reporting on a grouped average over a group of records

Tag : sql , By : user147496
Date : March 29 2020, 07:55 AM
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