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XSLT: Omit last newline in output


XSLT: Omit last newline in output

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XSLT: Omit last newline in output
Tag : xml , By : Ed.
Date : November 28 2020, 11:01 PM

hop of those help? I am have the following xml file: , I. Just look ahead, if there is any following sibling tr:
<xsl:template match="/table/tr">
    <xsl:value-of select="./td[1]" />
    <xsl:if test="following-sibling::tr">
        <xsl:text>&#xa;</xsl:text>
    </xsl:if>
</xsl:template>
<xsl:template match="/table/tr">
    <xsl:value-of select="./td[1]" />
    <xsl:text>&#xa;</xsl:text>
</xsl:template>

<xsl:template match="/table/tr[last()]" priority="1.1">
    <xsl:value-of select="./td[1]" />
</xsl:template>

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Ada: omit newline when redirecting to stdout (testing Put)


Tag : unit-testing , By : user181345
Date : March 29 2020, 07:55 AM
may help you . Sorry for my previous answer, I missed that the file you were reading was one you created earlier in the program.
In Ada.Text_IO, the RM (A.10(7-8)) says "the end of a file is marked by the combination of a line terminator immediately followed by a page terminator and then a file terminator", and "The actual nature of terminators is not defined by the language and hence depends on the implementation" ... "they are not necessarily implemented as characters or as sequences of characters". So when you create say_something_test.txt, it will always end with a "line terminator" although that doesn't necessarily mean it will end with an LF. That's implementation-dependent. The only thing you're guaranteed is that if you use Ada.Text_IO to create a file, it will work correctly if you read it back in with Ada.Text_IO. But if you want this level of control of the actual bytes written to the file, then Ada.Text_IO would not really be suitable; you'd be better off using Ada.Stream_IO.

Python - Replace newline with return carriage/newline in file output


Tag : python , By : Barry
Date : March 29 2020, 07:55 AM
I hope this helps you . You can use the open function from the io module. There you can specify the newline mode explicitly. Every '\n' is translated to '\r\n' in this example:
from io import open
with open("test.txt", "w+", newline="\r\n") as f:
    f.write(u"Hello World\n")
$ hexdump -C test.txt
00000000  48 65 6c 6c 6f 20 57 6f  72 6c 64 0d 0a           |Hello World..|
from io import open
with open(infname, 'r') as inf, open(outfname, "w+", newline="\r\n") as outf:
    outf.writelines(inf)

Regex: match words, omit newline


Tag : regex , By : Pancilobak
Date : March 29 2020, 07:55 AM
will help you I'm new to regex (and stackoverflow btw) and trying to extract "real" words out of this using R:
(?<=\\n)((?:(?!\\n).)*?)(?=\\nstar)

Omit the newline character in reading file with c++


Tag : cpp , By : Ir0nh1de
Date : October 18 2020, 01:08 AM
around this issue I have this code: , Use the stream operator >> to read integers:
std::ifstream path("test");
int number;
while(path >> number)
    std::cout << number << ", ";
std::cout << "END\n";
return 0;
if (line.size())
    cout << line[size()-1] << "\n";
#include <iostream>
#include <string>
#include <fstream>
#include <sstream>

int main()
{
    std::ifstream path("test");
    std::string line;
    while(getline(path, line))
    {
        std::stringstream ss(line);
        int number;
        while(ss >> number)
            std::cout << number << ", ";
        std::cout << "End of line\n";
    }
    std::cout << "\n";
    return 0;
}

Omit empty elements from XSLT 1.0 output


Tag : xml , By : Guy Kastenbaum
Date : March 29 2020, 07:55 AM
Hope this helps Try having a generic template that matches any element, but takes a parameter to allow that element to be renamed
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">

  <xsl:output method="xml" indent="yes" />
  <xsl:strip-space elements="*" />

  <xsl:template match="//Patients/Patient">
    <PatientRxs>
      <PatientInfo>
        <xsl:apply-templates select="Forenames" mode="field">
          <xsl:with-param name="newName" select="'FirstName'" />
        </xsl:apply-templates>
        <xsl:apply-templates select="VoicePhone" mode="field">
          <xsl:with-param name="newName" select="'Telephone'" />
        </xsl:apply-templates>
      </PatientInfo>
    </PatientRxs>
  </xsl:template>

  <xsl:template match="*" mode="field">
      <xsl:param name="newName" select="local-name()" />

      <xsl:element name="{$newName}">
          <xsl:value-of select="." />
      </xsl:element>
  </xsl:template>

</xsl:stylesheet>
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