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Append a list to ul


Append a list to ul

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Append a list to ul
Tag : javascript , By : Pieter Taelman
Date : November 28 2020, 11:01 PM

like below fixes the issue The problem was where you try to append the text as a child. li.appendChild('
  • '+i+'$'+profitday.toFixed(2)+'$'+profit.toFixed(2)+'
  • ');should be li.innerHTML = ''+i+'$'+profitday.toFixed(2)+'$'+profit.toFixed(2)+''
    function calc()
    {
        document.getElementById("calc_result").innerHTML;
        percent = 1;
        profit = 0;
        amount = document.getElementById("calc_amount").value;  
        if (amount>100000) amount = 100000;
        if (amount<10) amount = 0;
        for (var i = 1; i <= 365; i++) 
        {
            profit = parseFloat(profit) + parseFloat(amount*percent/100);
            profitday = parseFloat(amount*percent/100);
    
            var ul = document.getElementById("calc_result");
            var li = document.createElement("li");
            li.className = "cfix";
            li.innerHTML =  '<span>'+i+'</span><span>$'+profitday.toFixed(2)+'</span><span>$'+profit.toFixed(2)+'</span>'
            ul.appendChild(li);     
            if (percent<4) 
                percent += 0.5;
        }
    }
    

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    Python: “List.append = ‘list’ object attribute ‘append’ is read-only”


    Tag : python , By : AJacques
    Date : March 29 2020, 07:55 AM
    seems to work fine I’m trying to write a response from a Solr server to a CSV file. I’m pretty new to python and have been given code to modify. Originally the code looked like this ...
    >>> list.append
    <method 'append' of 'list' objects>
    
    docstats = []
    for doc in response.results:
        docstats.append(json.loads(doc['status']))
    
    docstats = [json.loads(doc['status']) for doc in response.results]
    

    Prolog How to append new variable to list using predicate like append([Item], List)?


    Tag : prolog , By : John Phipps
    Date : March 29 2020, 07:55 AM
    hop of those help? You need 3 elements: the element to be added, the list without element, the concatenation of these. Then you can't do with 2 elements only.
    Note that append([Item], List, Result) can be more conveniently written [Item|List] = Result, and Item will be the first element of Result. Then you're not appending. You can do with append(List, [Item], Result)

    How to append an element in a list a declared in global , while list.append() statement is inside a function


    Tag : python , By : user98986
    Date : March 29 2020, 07:55 AM
    I hope this helps you . corrected code for query , both var and result are global variables which are required to be accessed inside a function , Remove the word global from your append statement.
    You have:
    global result.append(var)
    
    result.append(var)
    

    Append a list to a list: AttributeError: 'NoneType' object has no attribute 'append'


    Tag : python , By : WellBeing
    Date : March 29 2020, 07:55 AM
    help you fix your problem append doesn't return an object. So you assigned None to the variable free.

    Python list append to list "AttributeError: 'tuple' object has no attribute 'append'"


    Tag : python , By : Jimmy
    Date : March 29 2020, 07:55 AM
    With these it helps Tuples are immutable meaning they can't be changed unless reassigned. You can however add tuples to a list because lists are mutable, meaning they can be changed. You need to edit the order of your append.
    listFollowedBy.append(row)
    
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