logo
down
shadow

List value is printing address instead of value


List value is printing address instead of value

Content Index :

List value is printing address instead of value
Tag : java , By : Cadu
Date : December 01 2020, 05:00 PM

seems to work fine Your object is of type List userBeans and you are trying to get value from userBeans[0].toString() which will obviously give you hash code of first element in List.
If you want to get value of case number from user bean in list you should probably use userBeans[0].getCaseNumber(); I am assuming you have getters for Case Number.

Comments
No Comments Right Now !

Boards Message :
You Must Login Or Sign Up to Add Your Comments .

Share : facebook icon twitter icon

Printing gives me a memory address on a class list rather than a specific STR


Tag : development , By : Anand
Date : March 29 2020, 07:55 AM
I wish did fix the issue. To get the list to print something other than the instance information you need to implement __repr__ on your Card class. The list container uses this function instead of __str__ to get the string representations for the objects it contains. This is mainly for debugging purposes and should uniquely identify the object.
So...First I added the following to your Card class.
def __repr__(self):
    return '%s of %s' % (Card.rank_names[self.rank], Card.suit_names[self.suit])
# Printing the whole list (which uses __repr__)
j=Deck()
foo = j.deal_hands(2,3)
print foo

# Printing the lists (which uses __str__)
for hand in foo:
  for card in hand:
    print card
$ python test.py 
[[King of Spades, Queen of Spades], [Jack of Spades, 10 of Spades], [9 of Spades, 8 of Spades]]
King of Spades
Queen of Spades
Jack of Spades
10 of Spades
9 of Spades
8 of Spades
import pprint
pp = pprint.PrettyPrinter(indent=4)
pp.pprint(foo)
[   [King of Spades, Queen of Spades],
    [Jack of Spades, 10 of Spades],
    [9 of Spades, 8 of Spades]]

tail->next printing address instead of data circular linked list c++


Tag : cpp , By : redha
Date : March 29 2020, 07:55 AM
seems to work fine Im trying to tie two ends together in my circular singly linked list. In the file name file.txt, containing ABCDEFGHIJKLMNOPQRSTUVWXYZ as text, I was able to print out the head and tail, A and Z, respectively. however, I'd like Z to point to A however my output is the address of A ( see below ). What am I doing wrong in addNode()?
#include <string.h>
#include <cstdio>
#include <cstdlib>
#include <stdio.h>
#include <stdlib.h>
#include <iostream>
#include <fstream>    // For file input
#include <cassert>    // for assertions
using namespace std;

    FILE *filename = fopen("file.txt", "r"); // Try to open file


struct Node
  {
  char data;
  Node* next;

  } ;

    void addNode( Node * &head, Node * &tail, char input)
      {
      Node *pTemp = new Node;
      pTemp->data = input;

       if( head == NULL)
          {
            head=tail =pTemp;
           tail->next=pTemp;

          }

      else
          {
          pTemp->next = tail->next;
          tail->next=pTemp;
          tail = pTemp;

          }


      }//end addNode()


    int main()
      {
      assert(filename);
      Node *head=NULL;
       Node *tail=NULL;
      char c =' ';
      int i=0;

      while( fscanf(filename,"%c", &c) != EOF)
        addNode( head,tail, c);



    cout<<endl;
    cout<<"\nHead element is "<<head->data<<endl;
    cout<<"Tail element is "<<tail->data<<endl;
    cout<<"After tail '"<<tail->data<<"' is : "<< tail->next->data<<endl;

      }
Node A
[A  | pointer to self] <- head and tail 
Node B
[A  | pointer to B ] <-head
[B  | pointer to A ] <-tail
Node C
[A  | pointer to B ] <-head
[B  | pointer to C ]  
[C  | pointer to A ]   <-tail

Node D
[A  | pointer to B ] <-head
[B  | pointer to C ]  
[C  | pointer to D ]    
[C  | pointer to A ]   <-tail

Printing an hexadecimal memory address of a node in a linked list in C


Tag : c , By : Johannes
Date : March 29 2020, 07:55 AM
hop of those help? ¤tPtr give you a pointer to the pointer variable, it's not where currentPtr is actually pointing. The value of ¤tPtr will not change in the loop, since the variable itself will not change location.
If you want to print where currentPtr is pointing, to the node itself, then print plain currentPtr.

Printing the list of unique first name last name phone number email and address details in excel using Python


Tag : python , By : Robert Daniel Pickar
Date : March 29 2020, 07:55 AM
may help you . We have created a python code to print "ABCD MNOP 282-567-4285 455 mindspace St., brisbane GA 35001 abcdmnop@gmail.com" which is nothing but First Name, Last Name, Mobile Number and Address , Try the following

import random
import xlsxwriter

first_names = ['ABCD', 'EFGH', 'IJKL', 'MNOP', 'QRST', 'UVWX', 'YZ']
last_names = ['ABCD', 'EFGH', 'IJKL', 'MNOP', 'QRST', 'UVWX', 'YZ']
street_names = ['indralok', 'mindspace', 'marine drive', 'kora kendra', 'bamdstand', 'mount mary', 'milan', 'paris','dubai', 'dindoshi', 'magathane', 'arnala']
cities_names = ['mumbai', 'banglore', 'pune', 'lucknow', 'patna', 'goa', 'ahmedabad', 'sydney', 'melbourne', 'brisbane','perth']
states = ['AL', 'AK', 'AZ', 'AR', 'CA', 'CO', 'CT', 'DC', 'DE', 'FL', 'GA', 'HI', 'ID', 'IL', 'IN', 'IA', 'KS', 'KY','LA', 'ME', 'MD', 'MA', 'MI', 'MN', 'MS', 'MO', 'MT', 'NE', 'NV', 'NH', 'NJ', 'NM', 'NY', 'NC', 'ND', 'OH','OK', 'OR', 'PA', 'RI', 'SC', 'SD', 'TN', 'TX', 'UT', 'VT', 'VA', 'WA', 'WV', 'WI', 'WY']

N = 10

workbook = xlsxwriter.Workbook('output.xlsx')
worksheet = workbook.add_worksheet()

def get_random_value(input_list):
    return input_list[random.randint(0, len(input_list)-1)]

worksheet.write(0, 0, "First Name")
worksheet.write(0, 1, "Last Name")
worksheet.write(0, 2, "Street")
worksheet.write(0, 3, "City")
worksheet.write(0, 4, "State")

for i in range(1,N+1):    
    worksheet.write(i, 0, get_random_value(first_names))
    worksheet.write(i, 1, get_random_value(last_names))
    worksheet.write(i, 2, get_random_value(street_names))
    worksheet.write(i, 3, get_random_value(cities_names))
    worksheet.write(i, 4, get_random_value(states))

workbook.close()

printing reference variable is not printing the object's address


Tag : java , By : Ted Leung
Date : March 29 2020, 07:55 AM
Related Posts Related QUESTIONS :
  • Unexpected Output while retrieving Data from mongodb and displaying in a csv file?
  • Algorithm for searching a value in two arrays
  • How to avoid casting with generic return values?
  • Java/RegEx - Negation of pattern not working
  • How to split a string to non empty words if it might include a separator like tab on first place
  • Supplier<Sequence<String>> cannot be iterated more than once
  • Why there is only one thread can actually started in @PostConstruct method?
  • Manage CompletionStage inside of Netty handler
  • Url Problem while Developing on Localhost and deploy on Remote Virtual Server
  • How to identify the missing type id in Jackson error?
  • android data binding error: cannot find symbol
  • Spring Boot application with a jar dependency does not run after maven build
  • Spring Data JPA query , filter ? search engine ? JPQL?
  • Why LiveData returns null in ViewModel?
  • what this line of code mean....new URLClassLoader(new URL[0],getClass().getClassLoader());
  • Why do need to use new Random() instead of just Random Randomnum?
  • I want to access zk components from the java file
  • How do I cast FieldValue.serverTimestamp() to Kotlin/Java Date Class
  • Insertion Sort Double Array with User Input - JAVA
  • Creating 2 dimesional array with user input and find sum of specific columns
  • can not get Advertising ID Provider in android
  • Convert list of Objects to map of properties
  • How to represent an undirected weighted graph in java
  • Return values as array from collection
  • ByteBuddy generic method return cast to concrete type
  • ImageView hides the round corners of the parent
  • Is there a way to find setter method by its getter method or vice versa in a class?
  • Get aggregated list of properties from list of Objects(Java 8)
  • Unable to find a document in Mongodb where exact date match in java
  • UsernamePasswordAuthenticationFilter skips success handler
  • Use Java filter on stream with in a stream filter
  • Default Login not successful in spring boot 2.1.7
  • Adding key value pairs from a file to a Hashmap
  • Rub regex: matching a char except when after by another char
  • Convert Base64 String to String Array
  • Escape Unicode Character 'POPCORN' to HTML Entity
  • An empty JSON field which is a boolean/nullable field in Java model, is getting converted as null
  • Mongo java driver cannot find public constructor for interface
  • How to unit test writing a file to AWS Lambda output stream?
  • How to make a GitHub GraphQL API Call from Java
  • What's the difference between @ComponentScan and @Bean in a context configuration?
  • Expected class or package adding a view using a class
  • can be delete of a element in a static array be O(1)?
  • Instance variable heap or stack ? ( with specific example)
  • Assert progress of ProgressBar in Espresso test
  • How to detect if gson.fromjson() has excess elements
  • I cant generate the proper code to select the a specific filter on a BI dashboard I am working on
  • How to Inject Dependencies into a Servlet Filter with Spring Boot Filter Registration Bean?
  • Thrift types as a Generic
  • Effective algorithm to random 4 unique integers less than a big max such as 100_000
  • Combining or and negation in Java regex?
  • Unable to instantiate default tuplizer Exception
  • Multi-tenant migration to work with quarkus
  • Ignite persisting a Set: Cannot find metadata for object with compact footer
  • Maven cannot resolve Jacob dependency using eclipse
  • testcontainers oracle database container starts before database user is created
  • Launching two spring boot apps in integration test
  • Is there a way to add a HashMap's value that is a integer array into a ArrayList?
  • Is there any way that I can get a parameter in paintComponent?
  • Empty stack with one recursive method and one iterative method
  • shadow
    Privacy Policy - Terms - Contact Us © scrbit.com