Simultaneous assignment in Go
Date : March 29 2020, 07:55 AM
should help you out It is very easy to make mistakes like a, b = a, b and not a, b = b, a, tmp = a
a = b
b = tmp
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Simultaneous assignment semantics in Python
Date : March 29 2020, 07:55 AM
Does that help Consider the following Python 3 code: , In this case: i, a[i] = i + 1, i
>>> a = [0,0,0,0]
>>> i, a[i], i, a[i] = range(4)
>>> a
[1, 0, 3, 0]
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Simultaneous variable assignment and printing
Date : March 29 2020, 07:55 AM
should help you out I was wondering if there was a way to assign a value and print the value to the console succinctly. , You can try: (x <- 1:5)
print(x <- 1:5)
(names(x) <- letters[1:5])
(x <- setNames(x, letters[1:5]))
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Simultaneous column assignment
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , You can use ix to set multiple columns at the same time without problem: In [8]:
df = pd.DataFrame({'a':np.random.randn(5), 'b':np.random.randn(5), 'c':np.random.randn(5)})
df
Out[8]:
a b c
0 0.623686 0.875752 1.027399
1 -0.806096 0.349891 0.290276
2 0.750623 0.704666 -1.401591
3 -0.594068 -1.148006 0.373021
4 -1.060019 -0.325563 -0.536769
In [9]:
df.ix[:,['a','b','c']] = 'total'
df
Out[9]:
a b c
0 total total total
1 total total total
2 total total total
3 total total total
4 total total total
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How to understand this simultaneous assignment evaluation in python 3?
Date : January 02 2021, 06:48 AM
this one helps. I am not understanding why y = 8 instead of y = 10 despite x = y = 5 being evaluated first x, y = y, (x+y)
x, y = 3, 5
temp = y, x + y
x, y = temp
>>> import dis
>>> def f(x, y):
... x, y = y, x + y
...
>>> dis.dis(f)
2 0 LOAD_FAST 1 (y)
2 LOAD_FAST 0 (x)
4 LOAD_FAST 1 (y)
6 BINARY_ADD
8 ROT_TWO
10 STORE_FAST 0 (x)
12 STORE_FAST 1 (y)
14 LOAD_CONST 0 (None)
16 RETURN_VALUE
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