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# Generate a normal distribution within certain limits in R

## Generate a normal distribution within certain limits in R Tag : r , By : simonth Date : December 01 2020, 05:00 PM

fixed the issue. Will look into that further I would like to generate a normal distribution with a mean of 120 and a standard deviation of 20. But I need to limit the values to [0, 150]. What should I do? , Instead of a while loop, you can use a recursion approach:
``````foo = function(n, m, v, up, down)
{
if(n==0) return(numeric(n))
vec = Filter(function(x) x>=down & x<=up, rnorm(n, m, v))
c(vec, foo(n-length(vec), m, v, up, down))
}

result = foo(1000, 120, 20, 150, 0)
``````

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## Find a python transformation function or numpy matrix to transform skewed normal distribution to normal distribution

Tag : python , By : snapshooter
Date : March 29 2020, 07:55 AM
this one helps. I've done one of 2 things:
Use box-cox transformations. This requires you find the appropriate power or lambda that transforms you data to having zero skew. Force a normal distribution.
``````from scipy.stats import norm

df = pd.DataFrame(np.random.rand(1000), columns=['Uniform'])
df['Normal'] = norm.ppf((df.Uniform.rank() - .5) / len(df))
df.plot(kind='kde')
``````
``````df.skew()

Uniform    2.392991e-02
Normal     2.114051e-15
dtype: float64
``````

## How to generate following error distributions? (contaminated normal distribution, A normal heteroscedastic distribution

Tag : r , By : Nick Coats
Date : March 29 2020, 07:55 AM
seems to work fine In relation to your first question, as mentioned by @Glen_b, you could use e.g.:
`````` cont_norm <- function(n, # number of samples
mu = 0, # only one mu since the mean is the same for both distributions.
sd1 = 1, # sd of the first distr
sd2 = 102, # sd of the second distr
prob = 0.1 # contamination proportion
){
s <- sample(c(sd1, sd2), n, replace = T, prob = c(1 - prob, prob))
rnorm(n, mean = mu, sd = s)}

cont_norm(100, mu = 0, sd1 = 1, sd2 = 102, prob = 0.1)
``````

## Limits involving the cumulative distribution function of a normal variable

Tag : python , By : Robert Daniel Pickar
Date : March 29 2020, 07:55 AM
it helps some times At present, a limit involving the function erf (known as the error function, related to normal CDF) can only be evaluated when the argument of erf tends to positive infinity. Limits at other places are either not evaluated, or evaluated incorrectly. (Related PR). This includes the limit
``````limit(-(sqrt(2)*x - sqrt(pi)*erf(sqrt(2)*x/2))/(2*sqrt(pi)*x**3), x, 0)
``````
``````series(func, x, 0, 1).removeO()
``````

## Generate numbers from normal distribution

Tag : r , By : thatotherguy
Date : March 29 2020, 07:55 AM
This might help you I know that if I want to generate for example 120 numbers from normal distribution with mean 30 and standard deviation 20 i can do it by command : , As proposed by @duckmayr
``````replicate(100, rnorm(120, 30, 20), simplify = TRUE) # if you want to generate a matrix

replicate(100, rnorm(120, 30, 20), simplify = FALSE) # if you want to generate a list
``````

## How to generate a Cumulative Normal Distribution in PHP

Tag : php , By : pdkent
Date : March 29 2020, 07:55 AM