Don't I have to call super() in constructor when class extends Sprite in actionscript3?
Date : March 29 2020, 07:55 AM
it should still fix some issue If flash doesn't detect a call to super() in your child constructor then flash will implicitly call super() before your child's constructor. So: public class Parent {
public function Parent() {
trace("Parent");
}
}
public class Child extends Parent {
public function Child() {
trace("Child");
}
}
new Child();
// Parent
// Child
public function Child() {
super(); // <-- Added by flash!
trace("Child");
}
public class Child extends Parent {
public function Child() {
trace("Child");
super()
}
}
public class Child extends Parent {
public function Child() {
// work before initilizing parent
super()
// work after initilizing parent
}
}
public class Child extends Parent {
public function Child() {
if(false) super()
}
}
|
Class<? super T> in getSuperclass() Does it make sense?
Tag : java , By : BinaryBoy
Date : March 29 2020, 07:55 AM
like below fixes the issue The bound is just a overly-broad because it's as close as you can express using Java's generics. What you really want is ; but there's no way to write that in Java's generics. There's also no way to write super T excluding T>. super T> is pretty much as specific as you can get given the way Java's generics work.
|
Makes it sense to create an object of a class which extends Service?
Date : March 29 2020, 07:55 AM
hope this fix your issue Although you can create an object of a class that extends Service but it doesn't make any programmatic sense. The fundamental reason to create an object is to use functionalities that class offer. In android paradigm, you would rather bind to a service to use its functionalities.
|
Java. Super call in class which extends Object
Tag : java , By : user130518
Date : March 29 2020, 07:55 AM
will help you First of all I recommend reading the source - documentation. Then a quote of jb-nizet's answer: class MyClass{
private int a;
public MyClass(int a){
super(); //what purpose of this?
this.a = a;
}
//other class methods here
}
class Foo extends Bar{
private int a;
public Foo(int a){
super(); //what purpose of this?
this.a = a;
}
//other class methods here
}
class Bar {
public String toString() {
return "bar";
}
}
class Foo extends Bar{
String foo = "foo";
public Foo(){
super(); //what purpose of this?
}
public String toString() {
super.toString()
}
|
How to make an extends object turn to its super object
Date : March 29 2020, 07:55 AM
|