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Should I ever prefer operators overloading over functions/methods?


Should I ever prefer operators overloading over functions/methods?

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Should I ever prefer operators overloading over functions/methods?
Tag : swift , By : Simone
Date : December 01 2020, 05:00 PM

Any of those help The main reason for overloading is comfort of using custom class with mathematic or logic background
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Overloading operators with non-member functions


Tag : cpp , By : Sebastian Gift
Date : March 29 2020, 07:55 AM
like below fixes the issue With a member function, this would be the left hand side parameter, meaning your operator would only have one argument (or none for unary operators). With a freestanding function, you must supply either two or one arguments for binary or unary operators, respectively.
A good example is the << operator for streams:
class T;

// ...

std::ostream & operator<<(std::ostream &os, const T &val)
{
    // ...
    return os;
}
std::cout << "Hello";
operator<<(std::cout, "Hello");

C# Error: The call is ambiguous between the following methods or properties. Overloading operators


Tag : chash , By : Asbie
Date : March 29 2020, 07:55 AM
like below fixes the issue No, it's got nothing to do with different namespaces - it's that you've got the same operator signature declared in two places:
public static Dollar operator +(Euro eu, Dollar dol)
public static Euro operator +(Euro eu, Dollar dol)
// In Dollar
public Dollar Plus(Euro eu)

// In Euro
public Dollar Plus(Dollar dol)
Euro euro00 = new Euro(1);
Dollar dollar00 = new Dollar(1);

Euro sumaEuros = euro00.Plus(dollar00);
public static Dollar operator +(Dollar dol, Euro eu)    
public static Euro operator +(Euro eu, Dollar dol)
Dollar dol1 = ...;
Euro eu1 = ...;

Dollar dol2 = dol1 + eu1;
Euro eu2 = eu1 + do1;

Overloading operators using extension methods


Tag : chash , By : Jonathan Bernard
Date : March 29 2020, 07:55 AM
Does that help C# already "lifts" all operators onto nullable types.
If either operand is null, the operator will return null.

Overloading I/O operators with a non-friend method in C++ | &istream and &ostream functions


Tag : cpp , By : ChaseVoid
Date : March 29 2020, 07:55 AM
I hope this helps . Just create [virtual] member functions read() and write() each taking a corresponding stream and call them from the respective operator:
class String {
    // ...
public:
    virtual std::istream& read(std::istream& in);
    virtual std::ostream& write(std::ostream& out) const;
};
std::istream& operator>> (std::istream& in, String& s) {
    return s.read(in);
}
std::ostream& operator<< (std::ostream& out, String const& s) {
    return s.write(out);
}

C++14 type lists, any reason to prefer 'free functions' to 'methods' or vice versa?


Tag : cpp , By : user181945
Date : March 29 2020, 07:55 AM
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