Join postgres table on two columns?
Date : March 29 2020, 07:55 AM
will help you I can't find a straightforward answer. My query is spitting out the wrong result, and I think it's because it's not seeing the "AND" as an actual join. , This is possible:
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Join large table with small table in postgres with index
Date : March 29 2020, 07:55 AM
Does that help I think your confusing from clause originates from the fact that you want the column default to be 12. To avoid that just declare the default when adding the column alter table mydb.mortgageloans
add column OriginalHPI varchar(130) default '12';
update edp_data.rmb_loan a
set OriginalHPI = (
case substring(a.edcode::text, 5, 2)
when 'NL' then c.nl
when 'BE' then c.be
when 'ES' then c.es
when 'FR' then c.fr
when 'IT' then c.IT
when 'DE' then c.de
when 'IE' then c.ie
else 12
end)::numeric
from edp_data.hpi c
where a.ar55 = c.period
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postgres join on same table
Tag : sql , By : user161314
Date : March 29 2020, 07:55 AM
this one helps. I have a table that looks like this , Subqueries: select x1.*, y2.y
from
(
select years, type, value as x
from MyTable
where x = 'true'
) x1
left join
(
select years, type, value as y
from MyTable
where y = 'true'
) y2
on x1.years = y2.years
and x1.type = y2.type
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In postgres, what is the best way to do an AND with a join table?
Tag : sql , By : boonchew
Date : March 29 2020, 07:55 AM
To fix the issue you can do I have different categories of user, and a join table that allows users to be in more than one category. My join table is called categories_users and it consists of a user_id and a category_id. , Just join with the same table twice (using aliases): SELECT u.*
FROM users u
JOIN categories_users cu1 ON cu1.user_id = u.id
JOIN categories_users cu2 ON cu2.user_id = u.id
WHERE cu1.category_id = 1 AND cu2.category_id = 2
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Join table not working in postgres
Date : March 29 2020, 07:55 AM
Hope this helps You need to convert the time and date value that you have in different columns (why?) to a single timestamp in order to be able to join on a timestamp column. Adding a time value on a date value returns a timestamp, so you can use: ON (TOTALIZER_METER_READINGS.date + TOTALIZER_METER_READINGS.time) = tt.mints
select distinct TOTALIZER_METER_READINGS.date + TOTALIZER_METER_READINGS.time
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