How to find recurring word groups in text with C#?

How to find recurring word groups in text with C#?

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How to find recurring word groups in text with C#?
Tag : chash , By : phatfish
Date : November 29 2020, 09:01 AM

To fix the issue you can do I'm getting recurring word counts in StringBuilder(sb) with this code which i've found on internet and according to writer it's really consistent like Word's word counter. , I think that this works fairly well.
var text = @"The green algae (singular: green alga) are ..."; // include all your text

var remove = "().,:[]0123456789".Select(x => x.ToString()).ToArray();

var words =
        .Matches(text, @"(\S+)")
        .SelectMany(x => x.Captures.Cast<Capture>())
        .Select(x => remove.Aggregate(x.Value, (t, r) => t.Replace(r, "")))
        .Select(x => x.Trim().ToLowerInvariant())
        .Where(x => !String.IsNullOrWhiteSpace(x))

var groups =
    from n1 in Enumerable.Range(0, words.Length)
    from n2 in Enumerable.Range(1, words.Length - n1)
    select String.Join(" ", words.Skip(n1).Take(n2));

var frequencies =
        .GroupBy(x => x)
        .Select(x => new { wordgroup = x.Key, count = x.Count() })
        .OrderByDescending(x => x.count)
        .ThenBy(x => x.wordgroup.Count(y => y == ' '))
        .ThenBy(x => x.wordgroup)

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Regex match word groups and parts of previously matched word groups

Tag : php , By : clifton anderson
Date : March 29 2020, 07:55 AM
this will help The issue is that you want to catch overlapping patterns (like "having with" and "with the"). You can do this with a cunning bit of look-ahead. I haven't managed to combine into a single regex with this method yet, but you could do something like this:
$text = 'This is an example text to explain the problem I am having with the regular expression';

preg_match_all('/\b(\w{4,})\b/', $text, $matches1);
preg_match_all('/\b(?=(\w{4,}\s+\w{3,}))\b/', $text, $matches2);
preg_match_all('/\b(?=(\w{4,}\s+\w{3,}\s+\w{3,}))\b/', $text, $matches3);

var_dump(array_merge($matches1[1], $matches2[1], $matches3[1]));

Python - find recurring pairs/groups of values in dictionary

Tag : python , By : 22.
Date : March 29 2020, 07:55 AM
I hope this helps . I have the following script, which loops over a text file of css rules, and stores each rule and its properties in a dictionary(improvements to code welcome, I've only just started using Python): , Assign a different prime number to every css property, like:
    'diplay: block': 2
    'font-size: 10px': 3,
    'font-family: Helvetica': 5,
    'min-height: 1000px': 7,
    'overflow: hidden': 11,
    'width: auto': 13,
    'background: white': 17,
    '#cs_ht_panel': 390, # 2 * 3 * 5 * 13
    '*': 77, # 7 * 11
    '.leftContainerDiv': 255, # 3 * 5 * 17

Regex to find capture groups with last word and the rest of the text

Tag : regex , By : Vijayant Singh
Date : March 29 2020, 07:55 AM
it helps some times I am having trouble getting the correct regex to do the following. 17 & Under CP AAA with ^(?) (?)$ and should give me a capture of age = 17 & Under CP and division = AAA. The last word will always be the division. What am I missing?
^(?<age>.*?) (?<division>\S+)$

Find the frequency and location of a recurring word in a cell in excel

Tag : excel , By : drbillll
Date : March 29 2020, 07:55 AM
Does that help Without using you can use this formula:
=IFERROR(FIND($B$2,$B$1,1+IFERROR(VALUE(B4),0)),"not found")

Find all groups of 9 digits (\d{9}) up to a certain word

Tag : regex , By : pttr
Date : September 01 2020, 03:00 PM
seems to work fine The easiest way is to get the string before Sector and just search that:
split_string, _ = string.split("Sector")
nums = re.findall(r'\d{9}', split_string)
# ['706345519', '708393673', '706855190']
import regex as re
nums = re.findall(r'(\d{9}).*?Sector', string, overlapped=True)
# ['706345519', '708393673', '706855190']
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