this one helps. , Fixed number for all index var array = [0, 1, 2, 3];
array.map(
function(n){
return (n* number to be multiplied);
}
);
var array = [0, 1, 2, 3], numberToBeMultiplied = [1,3,5,7];
array.map(
function(n, i){
return n * numberToBeMultiplied[i];
});
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Javascript array, Parse each element multiply each element by 'x'
Date : March 29 2020, 07:55 AM
I wish did fix the issue. I don't think you can do what you're asking. If read your code correctly, each second you're rebuilding the array from JSON data. It's trivial to loop through the array afterwards and multiply each element, but a second later your going to rebuild the array with the new data and lose those multiples. You could simulate the effect by doing this: var factor = 1.2;
var multiplier = factor;
for (i = 0; i < dataArray.length; i++) {
dataArray[i] *= multiplier;
multiplier *= factor;
}

Multiply every element of an ndimensional array by a number in Ruby
Tag : ruby , By : WellBeing
Date : March 29 2020, 07:55 AM
will help you In Ruby, is there a simple way to multiply every element in an ndimensional array by a single number? , The longform equivalent of this is: [ 1, 2, 3, 4, 5 ].collect { n n * 2 }
class Array
def multiply_by(x)
collect { n n * x }
end
end
class Array
def multiply_by(x)
collect do v
case(v)
when Array
# If this item in the Array is an Array,
# then apply the same method to it.
v.multiply_by(x)
else
v * x
end
end
end
end

Multiply each element of an array by a number in C
Date : March 29 2020, 07:55 AM
wish helps you There is no shortcut you have to step through each element of the array. Note however that in your example, you may achieve a speedup by using int rather than float for both your data and multiplier.

Iterate into element array then multiply with any number?
Tag : php , By : Jonathan Bernard
Date : March 29 2020, 07:55 AM
wish of those help Just use array_walk (keep it stupid simple): array_walk($yourArray, function (&$item, $key) {
$item['net'] *= 1000;
});

fastest method to multiply every element of array with a number in Scala
Date : September 23 2020, 10:00 AM
wish help you to fix your issue Presumably you mean arr.head * value. Neither of these are "faster" in bigO terms; they're both O(N), which makes sense because it's right there in the description: you need to multiply "every" number by some constant.

