using enum in Javascript for month number against name

using enum in Javascript for month number against name

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using enum in Javascript for month number against name
Tag : javascript , By : besn
Date : November 28 2020, 09:01 AM

help you fix your problem enumMonth is an Object. To access the object property value by it's key, you can use bracket notation
var months = [undefined, 'Jan', 'Feb', 'Mar', 'Apr', 'May', 'Jun', 'Jul', 'Aug', 'Sep', 'Oct', 'Nov', 'Dec'];

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Converting month name to month number using JavaScript

Tag : javascript , By : Kristian Hofslaeter
Date : March 29 2020, 07:55 AM
Any of those help You could keep an object of key/value pairs where the key is the month name and the value is the month number:
var months = {
    January: 1,
    February: 2,
var monthNumber = months['April'];
var monthNumber = months.April;

Change the Month Number to Month name in javascript

Tag : javascript , By : Eniac
Date : March 29 2020, 07:55 AM
To fix this issue I have problem in java Script . , Have you tried:
months[chartsdata[i].MonthValue - 1]

How to populate number of days in month right after selecting the month and year in Javascript/PHP?

Tag : javascript , By : Kristian Hofslaeter
Date : March 29 2020, 07:55 AM
should help you out You should populate the bday select options with client-sided javascript, like in the snippet I made for you below. All you have to do is put your php that generates the year-options back in the example below (I can't put server-sided PHP in the example below). Enjoy!
Please note: this code will even automatically calculate the amount of days in each month! (February has 28, except in leap years, then it has 29!). Try February 1992 for example (that's a leap year).
function daysInMonth(month, year) {
  return new Date(year, month, 0).getDate();

$('#byear, #bmonth').change(function() {

  if ($('#byear').val().length > 0 && $('#bmonth').val().length > 0) {
    $('#bday').prop('disabled', false);

    var daysInSelectedMonth = daysInMonth($('#bmonth').val(), $('#byear').val());

    for (var i = 1; i <= daysInSelectedMonth; i++) {
      $('#bday').append($("<option></option>").attr("value", i).text(i));

  } else {
    $('#bday').prop('disabled', true);

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<label for="birthday">Birthday Year</label>
<select id="byear" name="byear" required>
  <option value="">Select Year</option>
  <option value="1994">1994</option>
  <option value="1993">1993</option>
  <option value="1992">1992</option>
  <option value="1991">1991</option>

<label for="birthday">Month</label>
<select id="bmonth" name="bmonth" required>
  <option value="">Select Month</option>
  <option value="1">January</option>
  <option value="2">February</option>
  <option value="3">March</option>
  <option value="4">April</option>
  <option value="5">May</option>
  <option value="6">June</option>
  <option value="7">July</option>
  <option value="8">August</option>
  <option value="9">September</option>
  <option value="10">October</option>
  <option value="11">Novermber</option>
  <option value="12">December</option>

<label for="birthday">Day</label>
<select id="bday" name="bday" required disabled>
  <option value="">Select Day</option>

Why does JavaScript: new Date(year, month, 0).getDate() return the number of days in the month?

Tag : javascript , By : perl
Date : March 29 2020, 07:55 AM
Hope that helps When you give a parameter out of range, the next larger time increment is adjusted to make the time valid. So:
> new Date(2016,2,1)
> new Date(2016,2,0)

Tag : javascript , By : Cosmin
Date : March 29 2020, 07:55 AM
it helps some times I have this code to display calendar slider to pick a date. It shows dates like 2017-09-17, 2017-09-18, 2017-09-19. , Replace this part of your code :
<p class="sportName mydate p-date" style="color:white; font-size: 12px; text-align: center;" ><?php echo $el; ?></p>
<p class="sportName mydate p-date" style="color:white; font-size: 12px; text-align: center;" >
    //echo $el;

    //convert date to month name
    $date = $el;
    $month_name =  ucfirst(strftime("%B", strtotime($date)));
    $day_number = ucfirst(strftime("%d", strtotime($date)));

    echo $month_name.' - '.$day_number;
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