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Loop through an array in user model to find a match


Loop through an array in user model to find a match

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Loop through an array in user model to find a match
Tag : ruby-on-rails , By : Mostapen
Date : November 28 2020, 09:01 AM

Hope that helps If you don't have too many objects in your database and you want to run a quick one-off script in the console you can do this:
desired_product_ids = [801, 808]
User.find_each do |user|
  unless (user.product_ids & desired_product_ids).empty?
    give_gift user
  end
end

def give_gift(user)
  # your gift logic
  user.save
end
User.where(<your condition here>).find_each do |user|
  give_gift user
end

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loop through array of dom objects and find first that match


Tag : javascript , By : onurtopcu
Date : March 29 2020, 07:55 AM
Hope this helps You can achieve this using jQuery with the jQuery.next function - http://api.jquery.com/next/.
For a set of html like this:
<nav><a class="showNext">Show Next</a></nav>
<div class="content" style="display:none">I'm hidden</div>
<div class="content">I'm Visible</div>
$('.showNext').bind('click', function(e) {
    e.stopPropagation();
    e.preventDefault();
    window.location.hash = $(this).next('.content:visible').attr('id') + 'marker';
});

How to find the match case using for loop in array


Tag : javascript , By : FuzzyHornet
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further Like @Marc B and @Terry say, you have just to do an intersection.
Here's a version without Jquery :
function intersection(a, b)
{
  var result = [], ai = 0, bi = 0;
  a.sort();
  b.sort();
  while( a.length > ai && b.length > bi )
  {  
     if(a[ai] < b[bi] ){
       ai++; 
     }
     else if(a[ai] > b[bi] ){ 
       bi++; 
     }
     else
     {
       result.push(a[ai]);
       ai++;
       bi++;
     }
  }
  return result;
}

var arr1 = [
    {'id':'1','name':'test1','value':'star','role':['monitor']},
    {'id':'2','name':'test2','value':'player','role':['monitor','Supervisor']},
    {'id':'3','name':'test3','value':'saviour','role':['Supervisor']},
    {'id':'4','name':'test4','value':'rock','role':['monitor']},
    {'id':'5','name':'test5','value':'rocky','role':['boxer','monitor']}
]

var arr2 = ['Supervisor','monitor'];

var arr3 = [];

arr1.forEach(function(value){
  if(intersection(value.role, arr2).length === arr2.length){
    arr3.push(value);  
  }
});

console.log(arr3);

loop through and compare 2 array lists and find a match


Tag : java , By : Ivan Belov
Date : March 29 2020, 07:55 AM
should help you out I have 2 array lists. I want to return the unique value between the two. How is this done? , I updated my question with the correct answer.

How can i find match string in array without loop


Tag : javascript , By : browe
Date : March 29 2020, 07:55 AM
wish help you to fix your issue You could find the string by using Array#includes.
var blocklist = ['jack', 'mark', 'jhon', 'fox'],
    str = "xxxxxxxxxxjackxxxxxxxxx",
    result = blocklist.find(s => str.includes(s));

console.log(result);

How can I find values in an array which match criteria, without using a for loop?


Tag : php , By : Thomas Gueze
Date : March 29 2020, 07:55 AM
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