Where to Add Checks for Validity in a Binary Search Tree
Tag : java , By : Michael
Date : March 29 2020, 07:55 AM
it should still fix some issue Your class will have contracts. A reasonable expectation for a binary search tree would be the contract that every such tree is indeed a binary search tree. This is called an invariant.
Every operation that manipulates such a tree should do it in such a way that this invariant is never broken.
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Is binary tree a binary search tree if tree is spread over multiple machines
Date : March 29 2020, 07:55 AM
around this issue BST has a property. it's each children will also be a BST. validate all the machine's binary tree and once you have the each machine BT is BST then get the root node of each machine's BT and then again validate the tree if it is BST from the root node.
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JavaScript Class solution for Validate Binary Search Tree
Date : March 29 2020, 07:55 AM
will be helpful for those in need Thank you guys for your answers. Now I understand the issue: LeetCode forces me to run the function isValidBST that takes the parameter root and return the result. Doing so solves it: class Solution {
constructor(root) {
this.root = root;
}
get result() {
return this.helper(this.root, -Infinity, Infinity);
}
helper(root, low, high) {
if (!root) return true;
else {
let val = root.val;
if (val <= low || val >= high) return false;
if (!this.helper(root.right, val, high)) return false;
if (!this.helper(root.left, low, val)) return false;
return true;
}
}
}
var isValidBST = function(root) {
const res = new Solution(root)
return res.result;
};
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Differences in implementation of a tree, binary tree and, binary search tree in python
Date : March 29 2020, 07:55 AM
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Function to check whether a binary tree is binary search tree or not working
Date : March 29 2020, 07:55 AM
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