Boost test fails with enum classes inside namespaces

Boost test fails with enum classes inside namespaces

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Boost test fails with enum classes inside namespaces
Tag : cpp , By : ZsA
Date : November 28 2020, 09:01 AM

With these it helps You need to define the operator inside the namespace if you want to make use of ADL.
#include <iostream>
#define BOOST_TEST_MODULE EnumExample
#include <boost/test/unit_test.hpp>

namespace A {

enum class Example {

std::ostream& operator<< (std::ostream& s, Example e)
    switch (e) {
        case A::Example::One: s << "Example::One"; break;
        case A::Example::Two: s << "Example::Two"; break;
    return s;

} // namespace A

    A::Example a = A::Example::One;
    A::Example b = A::Example::Two;

    // The following line works with or without the namespace
    std::cout << a << std::endl;

    // The following line does not work with the namespace - why?

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Use enum classes with Boost Test

Tag : cpp , By : Menno
Date : March 29 2020, 07:55 AM
I wish this help you You can disable printing of the type in question with BOOST_TEST_DONT_PRINT_LOG_VALUE(). From the Boost docs:
typedef std::pair<int,float> pair_type;


Boost Python 1.48 fails when exporting 32 bit enum

Tag : python , By : Frank Rotolo
Date : March 29 2020, 07:55 AM
this one helps. EDIT: Found by Tigger at work, documenting here for posterity:
Problem is in the definition of the enum_object struct. The underlying digit storage in base_object allows for either 15-bit digit (as shorts) or 30-bit digit (as int) granularity, but the base_object only contains enough space for either 2x 15-bit digits or 1x 30-bit digits. When a > 30-bit enumeration value is stored the encoding requires either 3 shorts or 2 ints depending on the format compiled. The result is that the name member occupies the space needed for the extra digit storage. The reference decrement fails because the value is laid into place where the name member expects to be.
struct enum_object
#if PY_VERSION_HEX >= 0x03000000
   PyLongObject base_object;
   PyIntObject base_object;
   PyObject* name;
void enum_base::add_value(char const* name_, long value)
    // Convert name to Python string
    object name(name_);

    // Create a new enum instance by calling the class with a value
    object x = (*this)(value);

    // Store the object in the enum class
    (*this).attr(name_) = x;

    dict d = extract<dict>(this->attr("values"))();
    d[value] = x;

    // Set the name field in the new enum instanec
    enum_object* p = downcast<enum_object>(x.ptr());
    p->name = incref(name.ptr());

    dict names_dict = extract<dict>(this->attr("names"))();
    names_dict[x.attr("name")] = x;

enum, classes, namespaces and long names

Tag : cpp , By : Big Ant
Date : March 29 2020, 07:55 AM
it helps some times First, you repeat stuff:
The name kSensorActive doesn't have to say Sensor if you already specified that it's a SensorStatus in the name. Or you could remove Sensor from SensorStatus if it's inside MySensor. Maybe both.
using Status = Sensors::MySensor::SensorStatus;

How to test Controllers under different namespaces and why this test fails?

Tag : ruby-on-rails , By : Laques
Date : November 28 2020, 01:01 AM

C# Namespaces inside classes?

Tag : chash , By : user181706
Date : March 29 2020, 07:55 AM
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