Unable to read and sort information from a text file in Java

Unable to read and sort information from a text file in Java

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Unable to read and sort information from a text file in Java
Tag : java , By : Cowtung
Date : November 28 2020, 09:01 AM

it should still fix some issue I'm attempting to read a text file using BufferedReader and sort the information within the file. The purpose is to load and be able to access information on maps for a game I'm making. The problem I have is that when my program tried to sort the information I get a NullPointerException. , you need to initialize your variable Map
Map = new Map[5]; //array of fixed size 5

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Eclipse, Unable to Read Text File in Java Class

Tag : java , By : s8k
Date : March 29 2020, 07:55 AM
should help you out I know that some people have already encountered this problem, but I am still unable to solve it.
public static void main(String[] args) {

        BufferedReader br = null;
        try {
            String sCurrentLine;
//          br = new BufferedReader(new FileReader("D:\\test.txt")); //Absolute File
            br = new BufferedReader(new FileReader("test.txt"));//Relative File
            while ((sCurrentLine = br.readLine()) != null) {

        } catch (IOException e) {
        } finally {
            try {
                if (br != null)br.close();
            } catch (IOException ex) {


How to read efficiently a huge text file in java and split its content to sort it?

Tag : java , By : user177910
Date : March 29 2020, 07:55 AM
wish of those help LinkedList is not particularly efficient in terms of memory and no good for the built in sort algorythims. I suggest you load each line into an Array List and split it only by the name (not each field as you don't need to break those up)
You can sort an ArrayList with Collections.sort and a custom comparator.

Unable to read simple text file Java

Tag : java , By : Sinisa Ruzin
Date : March 29 2020, 07:55 AM
hope this fix your issue Well, there are two types of exception - unchecked and checked. checked are the ones that are checked at compile time. So, when compiler says "10: error: unreported expection FileNotFoundExcpetion; must be caught or declared to be thrown" It means line inFile = new Scanner(new FileReader("input.txt")); throws checked exception which means that this method has an underlying risk that it can throw a FileNotFoundExceptionand hence you should handle it. So, wrap your code in try/catch block -
/** Import util for console input **/
import java.util.*;
import java.io.*;
/** Standard Public Declarations **/
public class costing
 public static void main(String[] args)

  Scanner inFile;
  try {
     inFile = new Scanner(new FileReader("Coursework/input.txt"));
     String name = inFile.next();
} catch (FileNotFoundException ex) {

How to read a portion of a text file to extract information to be used to create an object in Java

Tag : java , By : ChrisMe
Date : March 29 2020, 07:55 AM
I hope this helps you . So I've got a text file:
public class ThisClass {
private static final URL path =      ThisClass.class.getResource("TextFile.info");
private static final String TEXTFILE = path.getFile();

private String name;
private int loadingBays;
private int containerHandlingTime;
private int storageCapacity;

public ThisClass(String name, int loadingBays, int containerHandlingTime,
                 int storageCapacity) {
    this.name = name;
    this.loadingBays = loadingBays;
    this.containerHandlingTime = containerHandlingTime;
    this.storageCapacity = storageCapacity;


public static void main(String[] args) throws FileNotFoundException, IOException {
    BufferedReader br = null;
    FileReader fr = null;

    String sCurrentLine;

    br = new BufferedReader(new FileReader(TEXTFILE));

    String name = "";
    int loading = 0;
    int time = 0;
    int capacity = 0;

    int count = 1;

    int elemCount = 0;

    ThisClass[] classArray = new ThisClass[2];

    while ((sCurrentLine = br.readLine()) != null) {

        System.out.println("sCurrentLine = " + sCurrentLine);
        if (sCurrentLine.toLowerCase().startsWith("name")) {
            name = sCurrentLine.split(":")[1].trim();
        } else if (sCurrentLine.toLowerCase().startsWith("loading")) {
            loading = Integer.parseInt(sCurrentLine.split(":")[1].trim());
        } else if (sCurrentLine.toLowerCase().startsWith("container")) {
            time = Integer.parseInt(sCurrentLine.split(":")[1].trim().replace("ms", ""));
        } else if (sCurrentLine.toLowerCase().startsWith("storage")) {
            capacity = Integer.parseInt(sCurrentLine.split(":")[1].trim());
        if (count % 4 == 0) {
            classArray[elemCount] = new ThisClass(name, loading, time, capacity);
            elemCount += 1;

            System.out.println("name = " + name);
            System.out.println("loading = " + loading);
            System.out.println("time = " + time);
            System.out.println("capacity = " + capacity);

        if (!sCurrentLine.trim().equalsIgnoreCase(""))
            count += 1;

    for (ThisClass cl : classArray) {
        System.out.println("cl = " + cl);

public String toString() {
    return "name: " + this.name
            + "loadingBays: " + this.loadingBays
            + "handlingTime: " + this.containerHandlingTime
            + "capacity: " + this.storageCapacity;

Unable to read text file in Java using FileReader and BufferedReader

Tag : java , By : Juan Pablo
Date : March 29 2020, 07:55 AM
I wish did fix the issue. To confirm that you are having a class with the name FileReader, just use the full class name in the code :
java.io.Reader fr = new java.io.FileReader("testfile.txt");
java.io.BufferedReader br =  new java.io.BufferedReader(fr);
import java.io.*


Reader fr = new java.io.FileReader("testfile.txt");
BufferedReader br =  new BufferedReader(fr);
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