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Django - Context dictionary for attribute inside a class


Django - Context dictionary for attribute inside a class

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Django - Context dictionary for attribute inside a class
Tag : python , By : Harry Truman
Date : November 28 2020, 09:01 AM

will be helpful for those in need title is an instance attribute in your model that is why you are getting this error message that being said to get a list of all title value you can use the .values() method
blog_list = [post['title'] for post in BlogPost.objects.values('title')]

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Accessing a specific dictionary inside a dictionary - Django Templates


Tag : python , By : Paul Schwarz
Date : March 29 2020, 07:55 AM
may help you . I don't think there is a way of doing this with Django templates, and that you should do as I said in my comments, which I'll rewrite here -- with some edits -- to summarize the hole thing up.
--
{% for key, item in myDict.items %}
    {% for innerkey, inneritem in item.items %}
        ...

Django context dictionary DRY


Tag : python , By : Juan Pablo
Date : March 29 2020, 07:55 AM
I wish did fix the issue. If you have some data that you want to be available in all templates throughout your site, you could create a "context_processor". This is simply a function that returns a dictionary. That dictionary is added to the context (and therefore available in your template) when rendering any view with a RequestContext.
In your example you would create a module in an app with a single function:
def get_searchdata():
    spec_list = Speciality.objects.order_by('name')
    ins_list = Insurance.objects.order_by('name')
    dict_data = {'Specialties': spec_list,
            'Insurances' : ins_list}
    return dict_data
TEMPLATE_CONTEXT_PROCESSORS = (
    "django.contrib.auth.context_processors.auth",
    "django.core.context_processors.debug",
    "django.core.context_processors.i18n",
    "django.core.context_processors.media",
    "django.core.context_processors.static",
    "django.core.context_processors.tz",
    "django.contrib.messages.context_processors.messages",
    ...
    "myapp.mycontext_processors.get_searchdata"
)

Django: Extend context of class based view with Admin context


Tag : python , By : jay
Date : March 29 2020, 07:55 AM
it fixes the issue This might not be a correct answer, but I believed you could try something like this.
#!/usr/bin/python3

from django.contrib import admin

class MyTemplateView(TemplateView):
    def get_context_data(self, **kwargs):    
        context = super().get_context_data(**kwargs)
        context.update(admin.site.each_context(self.request))
        return context

Python adding reverse map dictionary attribute in a class inherited from dictionary


Tag : python , By : Stuka
Date : March 29 2020, 07:55 AM
it fixes the issue You did not use the functions in the superclass (dict). It is how you should implement it
class DictWithReverseMap(dict):
  def __init__(self):
    super(DictWithReverseMap, self).__init__()
    self.reversemap = dict()
  def __setitem__(self, key, item):
    super(DictWithReverseMap, self).__setitem__(key, item)
    self.reversemap[item] = key

hh= DictWithReverseMap()
hh['1'] = "a"
hh['2'] = "a"
hh['3'] = "b"

print hh.keys()
print hh['1']  # Remember to use quote around the number 1
print hh.reversemap['b']    # Remember to use quote around the letter b

Ordering dictionary in context Django


Tag : django , By : Kyle
Date : March 29 2020, 07:55 AM
wish of those help Databases with index on columns are really good at sorting. There's almost never a need to sort on the client side. You can almost always do it in the server. The funny part it you apparently know how to do it too.
 ....exclude(active=False).order_by('long_name')  # <--- this
department = Department.objects.get(pk=pk)
    programmes = Programme.objects.all().filter(department=department).exclude(active=False).order_by('long_name')
    return render(request, 'sysadmin/department.html',{'department': department, 'programmes': programmes,})
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