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PHP MySQL Login Failure


PHP MySQL Login Failure

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PHP MySQL Login Failure
Tag : php , By : user176445
Date : November 27 2020, 09:01 AM

With these it helps As I stated in comments:
mysql_error() doesn't mix with the mysqli_ API. Use mysqli_error($link)
SELECT * FROM `login-teachers`
<?php 
error_reporting(E_ALL);
ini_set('display_errors', 1);

// rest of your code
$db = mysqli_select_db($link, DB_DATABASE);
if(!$db) {
    die("Unable to select database");
}

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MVC4 - Facebook (Login Failure. Unsuccessful login with service.)


Tag : .net , By : al.
Date : March 29 2020, 07:55 AM
should help you out You must make it publicly available. To do this:
Login to https://developers.facebook.com Select Your App Click settings and ensure a contact email is set (If you dont have this you cant complete step 4) Click Status & Review Toggle ' Do you want to make this app and all its live features available to the general public?' switch

displaying error message in login page after login failure


Tag : jsp , By : Ken
Date : March 29 2020, 07:55 AM
this one helps. here is some part of code from login.jsp , Since you are already using scriptlet in your jsp, you can use:
<%
    if(null!=request.getAttribute("errorMessage"))
    {
        out.println(request.getAttribute("errorMessage"));
    }
%>
<c:if test="${not empty errorMessage}">
   <c:out value="${errorMessage}"/>
</c:if>

Wampserver login failure mysql windows 7


Tag : mysql , By : cashshadow
Date : March 29 2020, 07:55 AM
I hope this helps . Try restarting all the services by left-click on wamp icon.
Or try the solutions on phpMyAdmin is throwing a #2002 cannot log in to the mysql server phpmyadmin

Displaying error message in login page after login failure - If condition is not working


Tag : java , By : mux
Date : March 29 2020, 07:55 AM
This might help you i think your problem is because request.getAttribute(String arg) will return Object type value. and you are calling equals method to compare with String object so it will always return false.
You need to use toString() method to change the value to String
 if(request.getAttribute("loginResult") != null && "true".equals(request.getAttribute("loginResult").toString())) {
                out.println("inide if");

Failure to login using Facebook Sdk: java.lang.RuntimeException: Failure delivering result


Tag : android , By : scotta01
Date : March 29 2020, 07:55 AM
To fix this issue Inside MainActivity , Add this code in your ProfileFragment
@Override
public void onActivityCreated(Bundle savedInstanceState) {
    super.onActivityCreated(savedInstanceState);

    }

 @Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    }
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