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Windows phone 8.1 POST x-www-form-urlencoded not working


Windows phone 8.1 POST x-www-form-urlencoded not working

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Windows phone 8.1 POST x-www-form-urlencoded not working
Tag : chash , By : Steve Jones
Date : November 26 2020, 09:01 AM

may help you . I'm trying to send POST x-www-form-urlencoded request payway payment api in C#. , use NavigateToString("") and add html form inside and post it :D

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Angularjs $http.post to contact form 7 with content type application/x-www-form-urlencoded


Tag : angularjs , By : JSebok
Date : March 29 2020, 07:55 AM
should help you out To POST data with content type application/x-www-form-urlencoded, the data needs to be urlencoded. Use the $httpParamSerializer service:
//this.sendMessage = function(successCallback, errorCallback){    
this.sendMessage = function(){
    var config = {
        //USE serializer
        transformRequest: $httpParamSerializer,
        headers:{
          'Content-Type':'application/x-www-form-urlencoded',
          'Accept':'application/json, text/javascript, */*;q=0.01'
        }
     };

     var data = {
          '_wpcf7':4,
          '_wpcf7_version':4.7,
          '_wpcf7_locale':'en_US',
          '_wpcf7_unit_tag':'wpcf7-f4-p6-o1',
          'fname':'john',
          'email':'admin@example.com',
          'subject':'subject',
          'message':'message',
          '_wpcf7_is_ajax_call':1
    };


    //vvvv RETURN httpPromise
    return $http.post('/be/home', data, config);
 };

my request failed when the post 'content-type' is application/x-www-form-urlencoded and * form field param= { <this i


Tag : development , By : user171752
Date : March 29 2020, 07:55 AM
this will help The request is failed when I post request an API whose header content-type is 'application/x-www-form-urlencoded; charset=UTF-8' and post body is ' param = { this is a json object} '
And form field param = {"cityid":"2091afc3-bcd6-46d9-8033-3548ad10933b","areaid":"2d09f5e5-a07d-445c-9d8a-51eb436699a8","hosid":"0f226b63-58ad-44d7-bf23-25d0345276e1","deptid":"91c176f5-63ca-4b95-87c4-9f311864ff9b","barcode":"1000000000","mothername":"manual-mother1","pregweek":"21","pregday":"1","midentitycard":"","birthday":"2018-10-01 00:00" ...... and so on }

How to post request with spring boot web-client for Form data for content type application/x-www-form-urlencoded


Tag : spring-boot , By : Picoman Games
Date : March 29 2020, 07:55 AM
should help you out How To use spring boot webclient for posting request with content type application/x-www-form-urlencoded sample curl request with content type `application/x-www-form-urlencoded' , We can use BodyInserters.fromFormData for this purpose
webClient client = WebClient.builder()
                            .baseUrl("SOME-BASE-URL")                                                                      
                      .defaultHeader(HttpHeaders.CONTENT_TYPE,MediaType.APPLICATION_FORM_URLENCODED_VALUE)
                                        .build();
            return client.post().uri("SOME-URI)
                         .body(BodyInserters.fromFormData("username", "SOME-USERNAME")
                                            .with("password", "SONE-PASSWORD"))
                         .retrieve()
                         .bodyToFlux(SomeClass.class)
                         .onErrorMap(e->new MyException("messahe",e))
                         .blockLast();

        }

Http Post request with content type application/x-www-form-urlencoded not working in Spring


Tag : java , By : user178709
Date : March 29 2020, 07:55 AM

Sending form-data / application/x-www-form-urlencoded body for OpenWhisk/Kitura Swift HTTP POST Request


Tag : swift , By : snk
Date : March 29 2020, 07:55 AM
Hope this helps You can use request.readString() to read the body information in its raw format.
If you have the BodyParser middleware in play using:
router.all("/name", middleware: BodyParser())
router.post("/name") { request, response, next in
    guard let parsedBody = request.body else {
        next()
        return
    }

    switch parsedBody {
        case .urlEncoded(let data):
            let name = data["name"].string ?? ""
            try response.send("Hello \(name)").end()
        default:
            break
    }
    next()
}
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