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# delete rows in numpy array in python

## delete rows in numpy array in python Tag : python , By : lhoBas Date : November 24 2020, 09:00 AM

around this issue In your proposed solution you are comparing with the integer 0, but the arrays consists of strings. So rows[1] == 0 will always give False. There's other things wrong with your solution as well.
Putting that aside, here's something that should work:
``````output = []
for C in my_input:
mask = ~np.all(C[:, 1:] != '0', axis=1)
``````
``````output = [C[~np.all(C[:, 1:] != '0', axis=1)] for C in my_input]
``````

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## How to delete last n rows from Numpy array?

Tag : python , By : Nic Doye
Date : March 29 2020, 07:55 AM
To remove the last n rows from an array:
``````a = np.array(range(10)).reshape(5, 2)
>>> a
array([[0, 1],
[2, 3],
[4, 5],
[6, 7],
[8, 9]])

n = 2  # Remove last two rows of array.
>>> a[:-n, :]
array([[0, 1],
[2, 3],
[4, 5]])
``````
``````>>> a[n:, :]  # Remove first two rows.
array([[4, 5],
[6, 7],
[8, 9]])
``````

## Python array rows*1column numpy for numpy.dot(matrix,matrix2)

Tag : python , By : user106284
Date : March 29 2020, 07:55 AM
I hope this helps . Is a = [1, 2, 3] x = numpy.array(a) a matrix of 3 cols and 1 row? I know that x = numpy.array([a]) is a 1x4 matrix but i need the opossite. I need to multiply two matrix but the first one is a list inserted into a numpy.array(a) , It is a 1 dimensional array:
``````In [653]: x = np.array([1,2,3])
In [654]: x
Out[654]: array([1, 2, 3])
In [655]: x.shape
Out[655]: (3,)
In [656]: x.ndim
Out[656]: 1
``````
``````In [657]: y = np.array([[1,2,3]])
In [658]: y
Out[658]: array([[1, 2, 3]])
In [659]: y.shape
Out[659]: (1, 3)
In [660]: y.ndim
Out[660]: 2
``````
``````In [661]: z = y.T
In [662]: z
Out[662]:
array([[1],
[2],
[3]])
In [663]: z.shape
Out[663]: (3, 1)
``````
``````In [664]: np.dot(x,y)
---------------------------------------------------------------------------
ValueError                                Traceback (most recent call last)
----> 1 np.dot(x,y)

ValueError: shapes (3,) and (1,3) not aligned: 3 (dim 0) != 1 (dim 0)
``````
``````In [665]: np.dot(y,x)
Out[665]: array([14])
``````
``````In [666]: x*y
Out[666]: array([[1, 4, 9]])
``````
``````In [667]: x*z
Out[667]:
array([[1, 2, 3],
[2, 4, 6],
[3, 6, 9]])
``````
``````In [671]: x[:,None]
Out[671]:
array([[1],
[2],
[3]])

In [672]: np.dot(x[:,None],y)
Out[672]:
array([[1, 2, 3],
[2, 4, 6],
[3, 6, 9]])
``````

## Delete all rows in a python numpy array that do not correspond to the top n values of a column

Tag : python , By : user152423
Date : March 29 2020, 07:55 AM
around this issue Since, the sorting needs to be done only on the 2nd column, you can use pandas. It makes the stuff a bit easier:
``````import pandas

In [725]: x
Out[725]:
array([[0, 3],
[1, 4],
[2, 5],
[3, 5],
[2, 4]])

Out[724]: [[2, 5], [3, 5], [1, 4]]
``````

## Delete some rows of a numpy array

Tag : python , By : CM.
Date : March 29 2020, 07:55 AM
With these it helps I have a numpy array like below , Take advantage of numpy's vectorized methods. Say your array is a:
``````trimmed = cf[(cf != 0).any(axis=1)]
``````

## How to delete multiple rows of NumPy array?

Tag : python , By : Stephen
Date : March 29 2020, 07:55 AM
may help you . There are several ways to delete rows from NumPy array.
The easiest one is to use basic indexing as with standard Python lists:
``````>>> import numpy as np
>>> x = np.arange(35).reshape(7, 5)
>>> x
array([[ 0,  1,  2,  3,  4],
[ 5,  6,  7,  8,  9],
[10, 11, 12, 13, 14],
[15, 16, 17, 18, 19],
[20, 21, 22, 23, 24],
[25, 26, 27, 28, 29],
[30, 31, 32, 33, 34]])
>>> result = x[5:]
>>> result
array([[25, 26, 27, 28, 29],
[30, 31, 32, 33, 34]])
``````
``````>>> x[:2, 1:4]
array([[1, 2, 3],
[6, 7, 8]])
``````
``````>>> x[[0, 2, 6]]
array([[ 0,  1,  2,  3,  4],
[10, 11, 12, 13, 14],
[30, 31, 32, 33, 34]])
``````
``````>>> np.take(x, [0, 2, 6], axis=0)
array([[ 0,  1,  2,  3,  4],
[10, 11, 12, 13, 14],
[30, 31, 32, 33, 34]])
``````
``````>>> np.delete(x, slice(0, 5), axis=0)
array([[25, 26, 27, 28, 29],
[30, 31, 32, 33, 34]])
>>> np.delete(x, [0, 2, 3], axis=0)
array([[ 5,  6,  7,  8,  9],
[20, 21, 22, 23, 24],
[25, 26, 27, 28, 29],
[30, 31, 32, 33, 34]])
``````
``````>>> mask_array = x[:, 0] < 12  # comparing values of the first column